小编Vam*_*esh的帖子

我已经MUSIC_PLAYER在我的应用程序中使用了这样开始:

Intent myint = new Intent("android.intent.action.MUSIC_PLAYER");
startActivity(myint);

我想暂停这个播放器.我怎么做？

import android.media.AudioManager;

import android.media.MediaPlayer;

import android.os.Bundle;

import android.app.Activity;

import android.content.Intent;

import android.view.Menu;

public class MainActivity extends Activity {

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        Thread mtr = new Thread(){
            public void run()
            {
                try {
                    Intent myint = new Intent("android.intent.action.MUSIC_PLAYER");
                    startActivity(myint);
                    sleep(50000);
                    // Here I want to pause my application after those 50 seconds.
                }
                catch(InterruptedException e){
                    e.printStackTrace();
                }
                finally{
                    Intent myint = new Intent("nextscreen");
                    startActivity(myint);
                }
            } …

我试图将我捕获的快照放在图像视图中.对于像nexus 7和sony xperiac这样的大型设备,它正在捕捉,但图像甚至不显示,我可以看到RESULT_OK,通过设置标志位那我现在该怎么办？

package gatesapps.blogspot.com;

import java.io.File;
import java.io.IOException;
import java.sql.Date;
import java.text.SimpleDateFormat;
import java.util.Random;

import android.annotation.SuppressLint;
import android.app.Activity;
import android.content.Intent;
import android.graphics.Bitmap;
import android.graphics.BitmapFactory;
import android.net.Uri;
import android.os.Bundle;
import android.os.Environment;
import android.provider.MediaStore;
import android.view.Menu;
import android.view.MenuItem;
import android.view.View;
import android.widget.Button;
import android.widget.ImageView;
import android.widget.TextView;
import android.widget.Toast;

public class MainActivity extends Activity {

String mCurrentPhotoPath;// for photo path
ImageView mImageView;
static boolean flag=false;

TextView tv;
Button test;
static final int REQUEST_TAKE_PHOTO = 1;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState); …

我正在尝试使用java创建一个http get请求,当我执行代码时,我正在获取403 forbidden代码.有没有办法摆脱它？我的代码是

 import java.io.BufferedReader;
 import java.io.InputStreamReader;
 import java.net.*;


public class Http {
private final String USER_AGENT = "Mozilla/5.0";
public static void main(String [] args){

    Http http=new Http();
    try {
        http.get();
    } catch (Exception e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

}
private void get() throws Exception{
    URL ob=new URL("http://www.google.com/search?q=vamsi");
    HttpURLConnection con=(HttpURLConnection) ob.openConnection();
    con.setRequestMethod("GET");
    con.setRequestProperty("USER_AGENT", USER_AGENT);
    int responseCode=con.getResponseCode();
    System.out.println("Response code is "+responseCode);
    BufferedReader buf=new BufferedReader(new InputStreamReader(con.getInputStream()));
    String input;
    StringBuffer response =new StringBuffer();
    while((input=buf.readLine())!=null){
        response.append(input);

    }
    buf.close(); …

我发现这个有趣的事实,解释似乎是工作的罚款python ex1.txt,但它应该是ex1.py.这可能是什么原因？是否有关于此类行为的任何文档.ex1.py或ex1.txt具有相同的print "hello",如果我有任何代码更改,这将更改.什么条件python ex1.txt可能不起作用.我用Google搜索并发现没什么好处.