在下面给出的示例中,未上传最后一行.我收到一个错误:
Data between close double quote (") and field separator:
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这看起来像一个bug,因为管道符号之间的所有数据都应该被视为一个字段.
Schema: one:string,two:string,three:string,four:string
上传文件:
This | is | test only | to check quotes
second | line | "with quotes" | no text
third line | with | "start quote" and | a word after quotes
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处理上面的第一行和第二行.但不是第三个.
更新:
有人可以解释为什么以下工作除了第三行?
This | is | test only | to check quotes
second | line | "with quotes" | no text
third line | with | "start quote" and | a …Run Code Online (Sandbox Code Playgroud) 从版本3.7.11开始,SQLite支持增强的INSERT语法,允许通过VALUES子句插入多行.
http://www.sqlite.org/releaselog/3_7_11.html
是否可以在单个语句中插入多少个值?(例如500)
我从下面链接获得的代码,可以将数据保存到磁盘.
http://tohyongcheng.github.io/python/2016/06/07/persisting-a-cache-in-python-to-disk.html
我试了但是文件没有生成.
import atexit
import pickle
# or import cPickle as pickle
def persist_cache_to_disk(filename):
def decorator(original_func):
try:
cache = pickle.load(open(filename, 'r'))
except (IOError, ValueError):
cache = {}
atexit.register(lambda: pickle.dump(cache, open(filename, "w")))
def new_func(*args):
if tuple(args) not in cache:
cache[tuple(args)] = original_func(*args)
return cache[args]
return new_func
return decorator
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我尝试按照示例使用此代码...
@persist_cache_to_disk('users.p')
def get_all_users():
x = 'some user'
return x
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更新:
这是在python命令提示符下工作,但在ipython笔记本中不起作用.
我正在努力解决一个棘手的问题并迷失方向.
这是我应该做的:
INPUT: file
OUTPUT: dictionary
Return a dictionary whose keys are all the words in the file (broken by
whitespace). The value for each word is a dictionary containing each word
that can follow the key and a count for the number of times it follows it.
You should lowercase everything.
Use strip and string.punctuation to strip the punctuation from the words.
Example:
>>> #example.txt is a file containing: "The cat chased the dog."
>>> with open('../data/example.txt') as f: …Run Code Online (Sandbox Code Playgroud) 我有一张这样的桌子......
select * from myescape;
+-----------+
| name |
+-----------+
| shantanu' |
| kumar's |
+-----------+
2 rows in set (0.00 sec)
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我需要用'\'替换单引号
我还需要避免双引号和反斜杠.
如果它们以/*开头并以*结尾,我如何删除所有注释?我尝试了以下操作.它适用于一行评论.
sed '/\/\*/d'
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但它不会删除多行注释.例如,不删除第二行和第三行.
/*!50500 PARTITION BY RANGE (TO_SECONDS(date_time ))
PARTITION 20120102parti VALUES LESS THAN (63492681600),
(PARTITION 20120101parti VALUES LESS THAN (63492595200) */ ;
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在上面的例子中,我需要保留最后一个; 在结束评论标志后.
在我的shell脚本中,我使用heredoc块来动态创建文件.什么是python等价物?
cat > myserver.pem << "heredoc"
-----BEGIN RSA PRIVATE KEY-----
MIIEpQIBAAKCAQEAnTsiYssvsuM1DRjyhqD8+ZB8ESqUFHgzeBYONp3yqjK8ICw/LRrxjXGXidAW
aPBXfktv3zN/kFsLMEFJKrJs/TLCfXG1CwFHMZzJRLM4aE6E0j6j+KF96cY5rfAo82rvP5kQdTIm
-----END RSA PRIVATE KEY-----
heredoc
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我正在寻找一个简单的解决方案.我非常喜欢上面的shell脚本代码.我可以在python中"按原样"使用它吗?
我试过这里的官方教程提供的例子:
http://saratoga.readthedocs.org/en/latest/serviceclasses.html
我对代码做了一些更改,这就是它的样子:
http://23.21.167.60:8094/v1/yearlength?name=earth
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我的问题是我需要在URL中提供account = 211829,就像name = earth一样.
我在下面写的是工作,因为我已经为班级提供了帐号.我该如何动态执行此操作?
import json
from saratoga.api import SaratogaAPI, DefaultServiceClass
class PlanetServiceClass(DefaultServiceClass):
def __init__(self, myaccount):
self.yearLength = {
"earth": self.myquery(myaccount),
"pluto": {"seconds": 7816176000}
}
def myquery(self, myaccount):
import pandas as pd
query = ('select * from mydata198 where account = %s ') % (myaccount)
import sqlalchemy
engine = sqlalchemy.create_engine('mysql+pymysql://dba:pass@1.2.3.4/test')
conn = engine.raw_connection()
df=pd.read_sql(query, conn)
return df.to_json()
class PlanetAPI(object):
class v1(object):
def yearlength_GET(self, request, params):
planetName = params["params"]["name"].lower()
return self.yearLength.get(planetName) …Run Code Online (Sandbox Code Playgroud) 我有这个功能在python中按预期工作.如何将其转换为AWS Lambda函数?
def mymailgun(url):
import urllib2
myfile=urllib2.urlopen(url)
import requests
print requests.post("https://api.mailgun.net/v3/XXX.mailgun.org/messages",
auth=("api", "key-XXX"),
files=[("attachment", myfile)
#("attachment", open("files/test.txt"))
],
data={"from": "Excited User <excited-user@example.com>",
"to": "XXX@gmail.com",
"cc": "YYY@yahoo.com",
"bcc": "ZZZ@hotmail.com",
"subject": "Hello",
"text": "Testing some awesomness with attachments!",
"html": myfile})
Run Code Online (Sandbox Code Playgroud) 我有一个用 Yaml 编写的大型 CloudFormation 模板,我想开始使用对流层。有没有什么简单的方法可以将 CF 模板转换为对流层代码?
我在这里注意到这个脚本https://github.com/cloudtools/troposphere/blob/master/troposphere/template_generator.py 这会创建一个对流层 python 对象,但我不确定是否可以输出它对流层代码。
python ×5
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