每次我尝试安装RMySQL时都会出现以下错误:
Installing package into ‘/home/ehsan/R/x86_64-pc-linux-gnu-library/3.0’
(as ‘lib’ is unspecified)
* installing *source* package ‘RMySQL’ ...
** package ‘RMySQL’ successfully unpacked and MD5 sums checked
checking for gcc... gcc
checking for C compiler default output file name... a.out
checking whether the C compiler works... yes
checking whether we are cross compiling... no
checking for suffix of executables...
checking for suffix of object files... o
checking whether we are using the GNU C compiler... yes
checking whether gcc accepts -g... yes
checking …Run Code Online (Sandbox Code Playgroud) 这似乎很简单,但我找不到办法.我需要显示整数的立方根是否为整数.我is_integer()在Python 3.4中使用了float方法但是没有成功.如
x = (3**3)**(1/3.0)
is_integer(x)
True
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但
x = (4**3)**(1/3.0)
is_integer(x)
False
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我想x%1 == 0,x == int(x)并isinstance(x,int)没有成功.
我很感激任何评论.
我正在浏览一些库,我注意到使用了一个包含幻影生命周期字段的结构,比如
struct S<'a> {
s: i32,
_lifetime: PhantomData<&'a ()> // NOTE: there's no generic type here!
}
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我很想知道幻影生命周期的重要性——它提供了什么好处S,没有它就不可能或不方便处理?
鉴于文档,我无法理解为什么联合上的模式匹配不能正常工作:
union A {
a1: i32,
a2: f32,
}
struct B(A);
let b = B(A { a2: 1.0 });
unsafe {
match b.0 {
A { a1 } => println!("int"),
A { a2 } => println!("float"),
}
}
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warning: unreachable pattern
--> src/main.rs:12:13
|
12 | A { a2 } => println!("float"),
| ^^^^^^^^
|
= note: #[warn(unreachable_patterns)] on by default
Run Code Online (Sandbox Code Playgroud) 我正在包装一个C API(dylib),它为最后一条错误消息公开了一个setter和getter API:
extern "C" {
/// GetLastError is thread-safe
pub fn GetLastError() -> *const ::std::os::raw::c_char;
pub fn SetLastError(msg: *const ::std::os::raw::c_char);
}
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包裹它们的最简单方法如下
use std::error::Error;
use std::ffi::CStr;
use std::fmt::{self, Display, Formatter};
use std::os::raw::c_char;
pub struct MyError;
impl MyError {
pub fn get_last() -> &'static str {
unsafe {
match CStr::from_ptr(c_api::GetLastError()).to_str() {
Ok(s) => s,
Err(_) => "Invalid UTF-8 message",
}
}
}
pub fn set_last(msg: &'static str) {
unsafe {
c_api::SetLastError(msg.as_ptr() as *const c_char);
}
}
}
impl Display for …Run Code Online (Sandbox Code Playgroud)