小编sha*_*rry的帖子

我有一个XML字符串,如下所示:

<s:Envelope 
xmlns:s="http://schemas.xmlsoap.org/soap/envelope/"><s:Body><Response 
xmlns="http://tempuri.org/"><UserResult><Users xmlns=""><User>
<Message>Success</Message>
<UserId>213213213</UserId>
<FullName>Abc</FullName>
<Roles>
<Role>
<RoleId>23232333</RoleId>
<RoleName>Salesperson</RoleName>
</Role>
</Roles>
</User>
</Users>
</UserResult></Response>
</s:Body>
</s:Envelope>

是否可以将XML转换为JSON？

我创建了一个通知方法,如下所示:

NotificationManager notificationManager = (NotificationManager) getSystemService(NOTIFICATION_SERVICE);
    Notification notification;

        notification = new Notification(R.drawable.messageicon, "You have a new message",
                System.currentTimeMillis());
        notification.flags |= Notification.FLAG_AUTO_CANCEL;

        RemoteViews view = new RemoteViews(getPackageName(), R.layout.notification);
        view.setImageViewResource(R.id.image, R.drawable.ic_launcher);
        view.setTextViewText(R.id.title, "New Message");
        view.setTextViewText(R.id.text, message);
        notification.contentView = view;
        Intent intent = new Intent();
        intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK | Intent.FLAG_ACTIVITY_CLEAR_TASK);
        PendingIntent activity = PendingIntent.getActivity(this, 0, intent, PendingIntent.FLAG_CANCEL_CURRENT);
        notification.contentIntent = activity;
        notificationManager.notify(0, notification);

我想在状态栏上添加一个按钮,单击该按钮时,应显示一个弹出窗口.任何帮助将受到高度赞赏.