我有功能规格测试：
describe "Reset password" do
let(:last_email) { ActionMailer::Base.deliveries.last }
it "should be success" do
# ...
page.should have_content t("users.passwords.sent")
last_email.to.first.should eq user.email
last_email.body.should have_content t("mail.body.recovery_instructions")
# Here is click_link
page.should have_content t("passwords.updated")
end
end
我如何单击位于的链接last_email.body？
我有以下哈希:
{
a: {
b: {
c1: "c1 value",
c2: "c2 value",
c3: {
d: "d value
}
}
}
如何将他转换为下一个结果:
{
"a.b.c1" => "c1 value",
"a.b.c2" => "c2 value",
"a.b.c3.d" => "d value"
}
我有一个阅读文件内容的功能.我需要通过引用从这个函数返回内容,我只是无法弄清楚如何String在函数内创建具有一定生命周期的mutable .
fn main() {
let filename = String::new();
let content: &String = read_file_content(&filename);
println!("{:?}", content);
}
fn read_file_content<'a>(_filename: &'a String) -> &'a String {
let mut content: &'a String = &String::new();
//....read file content.....
//File::open(filename).unwrap().read_to_string(&mut content).unwrap();
return &content;
}
输出:
error[E0597]: borrowed value does not live long enough
--> src/main.rs:8:36
|
8 | let mut content: &'a String = &String::new();
| ^^^^^^^^^^^^^ does not live long enough
...
14 | }
| - temporary value only lives …我有以下代码:
#/app/models/users/user.rb
class Users::User < ActiveRecord::Base
has_many :phones, class_name: "Users::Phone"
end
#/app/models/users/phone.rb
class Users::Phone < ActiveRecord::Base
belongs_to :user, class_name: "Users::User"
attr_accessible :phone
end
#/app/models/ability.rb
class Ability
include CanCan::Ability
def initialize(user)
can :read, :all
unless user.nil? #logged_in
if user.is? :admin
can :manage, :all
else
can :create, Users::Phone, user_id: user.id
end
end
end
end
我想检查为用户创建自己的手机的能力
#/app/views/users/users/show.html.slim
- if can? :create, Users::Phone.new
a[href="#{new_user_phone_path(@user)}"] Add phone
多数民众赞成不起作用,因为我应该将user_id传递给手机型号(如Users::Phone.new user_id: user.id),但我不能这样做,因为手机的质量分配.
那我怎么能检查:create手机的用户能力呢？
在javascript中有一个范围问题,并且无法解决如何传递一个值
$(document).ready(function() {
availableTags = new Array();
$.getJSON('index.php?getTagList', function(data) {
availableTags = data;
alert(data);
});
alert(availableTags);
});
我知道数据是正确的,警报确认了它,但我如何将它分配给availableTags变量？认真思考javascript中的范围......
我想将重命名的函数的名称设置回其实际名称。我已经能够生成 name ，但由于保留前缀，sub_123456使用MakeName(addr, name)aswell 和 as设置它总是失败。MakeNameEx(addr, name, flags)
有人已经能够实现这一点还是我必须使用自定义前缀？
谢谢
我对PHP框架的全新了.我一直在努力让帮助者整个上午工作,但他们拒绝这样做.我需要以某种方式启用它们吗？或者安装它们？
当我做:
<?php defined('SYSPATH') or die('No direct script access.');
class Controller_Api extends Controller {
public function action_index()
{
echo url::base();
}
去:
myurl/api
我明白了:
ErrorException [致命错误]:找不到类'Url'
谢谢你的帮助.
爱堆栈,我完全沮丧的第一篇文章.谢谢你的评论!
我已经复制了这个基本的GO程序来连接我的MySQL实例.
我构建并运行它.去构建mysqlexample.go ./mysqlexample
我无法实现成功的连接.您可以看到我尝试过的所有各种连接字符串,右边是我得到的响应.
我可以使用mysql admin从我的本地Windows机器连接.
救命？
package main
import (
"database/sql"
_ "github.com/go-sql-driver/mysql"
"log"
)
func main() {
const dbIP = "104.xxx.xx.x"
const dbInstanceName = "esp-1-dev:us-central1:espdev"
const dbName = "servpro"
const dbUserName = "root"
const dbPassword = "xxxxxxx"
const dbOpenString = dbUserName + ":" + dbPassword + "@/" + dbInstanceName + "/" + dbName //GETS RESPONSE default addr for network 'AppEngine:Zone:Project' unknown
//const …