小编Jon*_*aev的帖子

我尝试使用hibernate和jpa运行一个基本的应用程序,但是现在我在运行应用程序时遇到了这个异常......这是下面的代码和错误:

java.lang.IllegalArgumentException: Not an entity: class pka.EclipseJPAExample.domain.Employee
at org.hibernate.ejb.metamodel.MetamodelImpl.entity(MetamodelImpl.java:158)
at org.hibernate.ejb.criteria.QueryStructure.from(QueryStructure.java:136)
at org.hibernate.ejb.criteria.CriteriaQueryImpl.from(CriteriaQueryImpl.java:177)
at pka.EclipseJPAExample.jpa.JpaTest.createEmployees(JpaTest.java:47)
at pka.EclipseJPAExample.jpa.JpaTest.main(JpaTest.java:33)

JpaTest.java:

public class JpaTest {
private EntityManager manager;
public JpaTest(EntityManager manager) {
    this.manager = manager;
}
/**
 * @param args
 */
public static void main(String[] args) {
    EntityManagerFactory factory = Persistence.createEntityManagerFactory("persistenceUnit");
    EntityManager manager = factory.createEntityManager();
    JpaTest test = new JpaTest(manager);

    EntityTransaction tx = manager.getTransaction();
    tx.begin();
    try {
        test.createEmployees();
    } catch (Exception e) {
        e.printStackTrace();
    }
    tx.commit();

    test.listEmployees();

    System.out.println(".. done");
}

private void createEmployees() …