webpack 有没有办法自动内联样式？
例如，使用一些示例 CSS，
.example {
font-size: 2em
}
以及组件内的一些 HTML，
class Example extends React.Component {
render() {
return <div className={css.example} />
}
}
我希望 webpack 输出：
<div style="font-size: 2em;" />
说我有一个看起来像的字符串
'one, two, three,'
什么是pythonic方式迭代替换','与'.' 一次一个？理想情况下,函数的返回值如下所示:
['one. two, three,' , 'one, two. three,' , 'one, two, three.']
选择答案的推理,感谢您的贡献!
import timeit
def one(s):
b = ["%s.%s" % (s[:i], s[i+1:]) for i, c in enumerate(s) if c == ","]
def two(s):
b = [s[:i] + "." + s[i+1:] for i in range(len(s)) if s[i] == ","]
def thr(s):
b = [s[:i] + "." + s[i+1:] for i, c in enumerate(s) if s[i] == ","]
def fou(s):
ss = s.split(',') …我正在尝试创建一个基本的ruby scraper,它将从html源代码中获取8个字母或更长的单词.然后将它们保存在与单词的第一个字符对应的文件中.好像很简单吧？
re = /\w{8,}/
cre = /[a-z0-9]/
a = b.html #This grabs the html from the browser
matchx = a.scan(re)
matchx.each do |xx|
word = xx.to_s.downcase.chomp
fchar = word[0].chr
if (fchar.match(cre)) #Not sure if I need this
@pcount += 1
fname = @WordsFName+fchar #@WordsFName is a prefix
tmpF = File.open(fname,"a+")
#Check for duplicates, if not write to file
exists = File.readlines(fname).any? { |li| li[word] }
if (!exists)
tmpF.write(word+"\n")
print word
@wcount += 1
end
end
end
Ruby成功抓取所有单词,获取第一个字符,并打开所有必需的文件,但无法写入.此外,打印方法打印所有单词,包括重复,但检查任何？irb上的方法没有问题..