如果我把*放在我的正则表达式中,它就不起作用,如果我放+,它就可以了.
*应该是0或更多,+应该是1或更多.
案例*
$num = ' 527545855 ';
var_dump( preg_match( '/\d*/', substr( $num, 0, 18 ), $coincidencias ) );
var_dump($coincidencias);exit;
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结果:
int(1)
array(1) {
[0]=>
string(0) ""
}
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案例+
$num = ' 527545855 ';
var_dump( preg_match( '/\d+/', substr( $num, 0, 18 ), $coincidencias ) );
var_dump($coincidencias);exit;
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结果:
int(1)
array(1) {
[0]=>
string(9) "527545855"
}
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我认为两者都应该有效,但我不明白为什么*不起作用.
我不能让UL的li元素填充100%的宽度(或接近).
发生了一些奇怪的事情,因为第一列与父母的咆哮者相邻,但第二列与右侧父母的边界相差20磅.

.latest-posts .latest-posts-widget ul {
border: solid 1px;
}
.latest-posts .latest-posts-widget ul li {
display: inline-block;
width: 49%;
border: solid 1px;
}
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它受Bootstrap 3的影响
此外,我必须使用49%,因为50%不会使2列
Live page is under development in [www.hugotrinchero.com.ar][2]
Run Code Online (Sandbox Code Playgroud) 我想知道如何实现303重定向显示post数据.
例:
I send the form.
Redirect
Page displays the info I just posted. (Eg: Name, email).
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我认为它是用参数完成的,/index.php?name=TheName&email=theEmail但我不确定,因为我试图找到一些好的文章解释它但不能.
非常感谢.
我想知道如何在MySQL + PDO中获取警告计数.
在控制台中进行查询时,我发出警告,寻找varchar而不是添加aphostrophes(' ').
mysql> describe keywords;
+-------------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------------+--------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| document_id | int(11) | NO | MUL | NULL | |
| keyword | char(50) | NO | | NULL | |
| value | varchar(250) | YES | | NULL | |
+-------------+--------------+------+-----+---------+----------------+
4 rows in set (0.00 sec)
mysql> …Run Code Online (Sandbox Code Playgroud) 我是VB.net的新手,我无法编译这段代码,我不明白为什么.
MustInherit Class Poligono
Protected p_cant_Lados As Integer
Public Property cant_Lados() As Integer
Get
Return p_cant_Lados
End Get
Set(ByVal value As Integer)
p_cant_Lados = value
End Set
End Property
Public MustOverride Function obtenerPerimetro()
Public MustOverride Function cargarLados()
End Class
Public Class Triangulo
Inherits Poligono
Private lado1 As Integer
Private lado2 As Integer
Private lado3 As Integer
Public Function cargarLados() As Object
Return 1
End Function
Public Function obtenerPerimetro() As Object
Return 1
End Function
End Class
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错误2'Triangulo'不能从类'Poligono'继承,因为它扩展了程序集外部基类的访问.c:\ users\win7\documents\visual studio 2013\Projects\WindowsApplication1\WindowsApplication1\Form1.vb …
我在实体中有这段代码:
/**
* @ORM\ManyToOne(targetEntity="Centers")
* @ORM\JoinColumn(name="center_id", referencedColumnName="id")
* @ORM\Column(type="string", length=36, name="center_id")
*/
protected $centerId;
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然而,schema:update说一切都是同步的。即使将 Centers 更改为其他一些不存在的词,也不会产生错误。
get_the_post_navigation() 函数定义在里面 wp-includes/link-template.php
如何在主题中覆盖它?
我有这个:
msg = time + b' - ' + Logger.LEVELS_WORD[msg_loglevel] + b': ' + msg.encode('utf-8') + b'\n'
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由于有时 msg 已经是字节,如果它是字符串或者只是 msg,我想连接 msg.encode('utf-8'),所以我这样做了:
msg = time + b' - ' + Logger.LEVELS_WORD[msg_loglevel] + b': ' + msg if isinstance(msg, bytes) else msg.encode('utf-8') + b'\n'
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但它并没有像我预期的那样工作,因为现在msg equals msg。(时间 + 日志级别没有被添加)。
我应该做 if/else 吗?
例如,在以下代码中:
/**
* @Route("/patients", service="bundle1.controller.patient.index")
*/
final class IndexController
{
private $router;
private $formFactory;
private $templating;
private $patientFinder;
public function __construct(RouterInterface $router, FormFactoryInterface $formFactory, EngineInterface $templating, PatientFinder $patientFinder)
{
$this->router = $router;
$this->formFactory = $formFactory;
$this->templating = $templating;
$this->patientFinder = $patientFinder;
}
/**
* @Route("", name="patients_index")
*/
public function __invoke(Request $request) : Response
{
$form = $this->formFactory->create(PatientFilterType::class, null, [
'action' => $this->router->generate('patients_index'),
'method' => Request::METHOD_GET,
]);
$form->handleRequest($request);
$patients = $this->patientFinder->matching($form->getData() ?: []);
return $this->templating->renderResponse('patient/index.html.twig', [
'form' => $form->createView(),
'patients' => …Run Code Online (Sandbox Code Playgroud)