我有他们的名字具有结构的列nameUser.Name,但我无法更新它们.我尝试过几种可能性:
// Ideally, I'd like to do this (since the User.Name is 'dynamic', ie, it depends
// on who is logged in):
$userLogged = 'Some.User';
$columnName = 'name' . $userLogged;
mysql_query("UPDATE Industries SET '$columnName'='$name' WHERE id='$id'");
// Another try:
mysql_query("UPDATE Industries SET $columnName='$name' WHERE id='$id'");
// Alternatively, if the above cannot be achieved:
mysql_query("UPDATE Industries SET 'nameSome.User'='$name' WHERE id='$id'");
// Yet another try:
mysql_query("UPDATE Industries SET nameSome.User='$name' WHERE id='$id'");
但是,不是上述作品.为什么？
我已经在这里研究了所有的答案(/sf/answers/153371851/),但即使@davydepauw和@emeraldjava建议的最清晰的代码也不起作用......下面的代码没有选择/取消选择PHP代码中的框.
echo "<form action=$fileName method='post'>";
...
<script language='JavaScript'>
$('#select-all').click(function(event) {
if(this.checked) {
// Iterate each checkbox
$(':checkbox').each(function() {
this.checked = true;
});
}
else {
// Iterate each checkbox
$(':checkbox').each(function() {
this.checked = false;
});
}
});
</script>";
...
// This should select/deselect all checkboxes below:
echo "<input type='checkbox' name='select-all' id='select-all' />";
...
// The below is in the WHILE loop fetching data from MySQL:
echo "<input type='checkbox' name='IndustryID' value='" . $row['IndustryID'] . "'>";
...
</form>
对于@DavidThomas请求,下面是呈现的代码:
<body> …