小编gre*_*awk的帖子

我正在使用VMWare插件.我目前正在使用以下内容:

config.vm.network "public_network", ip: "172.17.255.13", netmask: "255.255.255.0"

它确实建立了BRIDGED连接,但它是一个BRIDGED DHCP连接.

有没有人成功使用静态IP？

这是一个CentOS-6.6 Box.

更新:这是特定的VM配置,创建者没有删除/ etc /中需要在VM打包之前清除的文件

这是在多个页面中使用smarty的最有效方法吗？:

if(empty($_GET[page])) {
 $template="home.tpl";
 $smarty->assign('pagename', ' - Home');
}else {
$page = $_GET["page"];
switch ($page) {
        case "home":
            $template="home.tpl";
             $smarty->assign('pagename', ' - Home');
            break;
        case "contact":
            $template="contact.tpl";
            $smarty->assign('pagename', ' - Contact us');
            break;
        case "verify":
            $template="verify.tpl";
            $smarty->assign('pagename', ' - Verify your account');
            break;
        default:
            $template="404.tpl";
            break;
    }

}

$smarty->assign('sitename', $sitename);
$smarty->display($template);

如果我有"登录"和"用户区"以及所有内容怎么办？我怎样才能使他们各自干净利落？

这就是我创建表的方式：

CREATE TABLE `item_spa_cust` (
    `id` INT(10) NOT NULL AUTO_INCREMENT,
    `spa_id` INT(10) NULL DEFAULT NULL,
    `type` VARCHAR(20) NOT NULL COLLATE 'latin1_swedish_ci',
    `is_valid` BIT(1) NOT NULL DEFAULT b'1',
    `company_name` VARCHAR(50) NULL DEFAULT NULL COLLATE 'latin1_swedish_ci',
    `custno` VARCHAR(6) NULL DEFAULT NULL COLLATE 'latin1_swedish_ci',
    PRIMARY KEY (`id`),
    INDEX `FK_item_spa_cust_item_spa` (`spa_id`),
    CONSTRAINT `FK_item_spa_cust_item_spa` FOREIGN KEY (`spa_id`) REFERENCES `item_spa` (`id`)) 
;

我希望该is_valid字段在设置时默认为“1”，但是，它始终默认为“0”。

我对此很困惑，请帮忙。

我的目标:

要捕获URL的最后一部分是否存在尾部斜杠,而不使用尾部斜杠作为URL上的字符串的一部分,类似于以下内容:

http://foo.com/p/dPWjiVtX-C/
                 ^^^^^^^^^^
               The string I want

我的问题:

我尝试的每一种方式只允许使用尾部斜杠而不是没有尾部斜杠的url,或者使尾部斜杠包含在我想要的字符串中.

我试过了什么？

1. 我试图斜线添加到末尾:

  $regex = "/.*?foo\.com\/p\/(.*)\//";
  if ($c=preg_match_all ($regex, $url, $matches))
  {
    $id=$matches[1][0];
    print "ID: $id \n";
  }

当我没有尾部斜杠时,这会导致错误.

2. 我已尝试添加一个问号:

  $regex = "/.*?foo\.com\/p\/(.*)[\/]?/";

这会导致斜杠(如果存在)位于我的字符串中.

我的问题/ tl;博士:

如何构建一个不需要斜杠的RegEx,但是将斜杠保留在前面的字符串中？

首先,这是一个.js小提琴:http://jsfiddle.net/B6DSv/

我遇到的问题是我的.css:

nav {
    overflow: hidden; /*THIS LINE*/
    background-color: #004b98;
    width: 100%;
    margin: 0;
    padding: 0;
}

和这里:

<nav>
    <ul>
        <li><a href="index.html">Home</a>
            <ul>
                <li><a href="#">teadsfasdfadsst</a></li>
            </ul>
        </li>

        <li><a href="#">Gallery</a></li>
        <li><a href="#">Map</a></li>
    </ul>
</nav>

如果我起飞overflow: hidden;,下拉工作......但我的背景被取消了.

我的目标：

按信用对用户的 json 列表进行排序。

我的问题：

积分已排序，但应按相反的顺序排序。

我的结果：

Position: 1
Username: abc
Credits: 12

Position: 2
Username: bcd
Credits: 123

Position: 3
Username: cde
Credits: 1245

我需要的：

Position: 1
Username: abc
Credits: 1234

Position: 2
Username: bcd
Credits: 123

Position: 3
Username: cde
Credits: 12

我的问题：

我怎样才能使名称按信用排序的正确顺序排列？

我的php代码：

<?php
$json = '{"id":1,"jsonrpc":"2.0","total":50,"result":[{"id":1,"username":"Ashley","credits":684921},{"id":2,"username":"Caroline","credits":113045},{"id":3,"username":"Alexandra","credits":669133},{"id":4,"username":"Katelyn","credits":735955},{"id":5,"username":"Ashley","credits":202478},{"id":6,"username":"Anna","credits":854266},{"id":7,"username":"Lily","credits":406425},{"id":8,"username":"Samantha","credits":430603},{"id":9,"username":"Caroline","credits":380785},{"id":10,"username":"Paige","credits":961596},{"id":11,"username":"Bailey","credits":67660},{"id":12,"username":"Kimberly","credits":610751},{"id":13,"username":"Maya","credits":446787},{"id":14,"username":"Maria","credits":818538},{"id":15,"username":"Ella","credits":789682},{"id":16,"username":"Olivia","credits":906604},{"id":17,"username":"Arianna","credits":177500},{"id":18,"username":"Maya","credits":592490},{"id":19,"username":"Aubrey","credits":58834},{"id":20,"username":"Sophie","credits":324357},{"id":21,"username":"Julia","credits":288688},{"id":22,"username":"Rachel","credits":932145},{"id":23,"username":"Arianna","credits":848696},{"id":24,"username":"Valeria","credits":272258},{"id":25,"username":"Autumn","credits":301136},{"id":26,"username":"Audrey","credits":317305},{"id":27,"username":"Chloe","credits":975642},{"id":28,"username":"Payton","credits":510533},{"id":29,"username":"Morgan","credits":927493},{"id":30,"username":"Mya","credits":166566},{"id":31,"username":"Lauren","credits":840207},{"id":32,"username":"Trinity","credits":255691},{"id":33,"username":"Jocelyn","credits":272653},{"id":34,"username":"Madeline","credits":58344},{"id":35,"username":"Valeria","credits":972228},{"id":36,"username":"Chloe","credits":919646},{"id":37,"username":"Jessica","credits":390647},{"id":38,"username":"Claire","credits":670709},{"id":39,"username":"Savannah","credits":47721},{"id":40,"username":"Zoe","credits":214133},{"id":41,"username":"Taylor","credits":991001},{"id":42,"username":"Gabrielle","credits":295506},{"id":43,"username":"Katherine","credits":295472},{"id":44,"username":"Vanessa","credits":600895},{"id":45,"username":"Olivia","credits":337541},{"id":46,"username":"Mackenzie","credits":32221},{"id":47,"username":"Bella","credits":461298},{"id":48,"username":"Maria","credits":318094},{"id":49,"username":"Lillian","credits":632622},{"id":50,"username":"Kayla","credits":17062}]}';
$decoded = json_decode($json);
$users = $decoded->result;

function my_sort($a, $b)
{
    if ($a-credits > $b->credits) {
        return -1;
    } else if ($a->credits < $b->credits) {
        return 1;
    } else { …

如果我有一个表格,其数据结构如下:

a,b
1,2
2,1
3,1

我想要做的是根据2个值a和b将这3行分为2行,如果组合在一行中共同存放到1行中,那么我可以进行计数查询.我想得到一个类似于的结果集:

a,b,count
1,2,2
3,1,1

所有它真正做的是让我必须调暗每个变量,如果我忘记调暗变量,它会严重编译.

有没有使用它的专业人士？

java如何计算这个？

int number = (int) Long.parseLong("F9DFF755", 16);

Long.parseLong("F9DFF755", 16); == 4192204629 (too big to be stored by an int)
Casted to int : -102762667

java如何强制插入int？