UFW 未登录任何位置。
ufw配置：
root@localhost:/var/log# ufw status verbose
Status: active
Logging: on (full)
Default: deny (incoming), allow (outgoing), deny (routed)
New profiles: skip
To Action From
-- ------ ----
2022/tcp ALLOW IN Anywhere
80 ALLOW IN Anywhere
2022/tcp (v6) ALLOW IN Anywhere (v6)
80 (v6) ALLOW IN Anywhere (v6)
root@localhost:/var/log#
rsyslog 配置：
root@localhost:/var/log# service rsyslog status
? rsyslog.service - System Logging Service
Loaded: loaded (/lib/systemd/system/rsyslog.service; enabled; vendor preset: enabled)
Active: active (running) since Tue 2017-02-21 18:43:33 CET; 5min ago
Docs: man:rsyslogd(8) …我在 Java 7 上使用 Spring 4.3.18 和 Spring Boot 1.5.14。
我正在实现一个 RestController 端点，它返回DeferredResult带有超时回调的 a 。我正在尝试为超时回调编写单元测试，但无法获得MockMvc调用超时回调的单元测试。
为了测试的目的，我写了这个端点：
@PostMapping("/test")
public DeferredResult<String>
testit() {
logger.info("testit called");
final DeferredResult<String> rv = new DeferredResult<>(1000L);
rv.onTimeout(new Runnable() {
@Override
public void run() {
logger.info("run called");
rv.setResult("timed out");
}
});
return rv;
}
和这个单元测试：
@Autowired
private MockMvc mockMvc;
@Test
public void testTest() throws Exception {
MvcResult result = mockMvc.perform(post("/rest/tasks/test"))
.andExpect(request().asyncStarted())
.andReturn();
result.getAsyncResult(1500);
mockMvc.perform(asyncDispatch(result))
.andExpect(status().isOk())
;
}
（调用result.getAsyncResult(1500)基于https://jira.spring.io/browse/SPR-16869）
当我运行此命令时，testit() …
我正在使用bookmarklet,我正在使用HTML DOM解析器获取任何外部页面的所有照片(如前面的回答所提出的那样).我正确地提取照片并显示在我的书签中弹出.但我对照片的相对路径有问题.
例如,外部页面上的照片来源说http://www.example.com/dir/index.php
照片来源1:img source ='hostname/photos/photo.jpg' - 获取照片,因为它是绝对的
照片来源2:img source ='/ photos/photo.jpg' - 没有得到,因为它不是绝对的.
我通过当前的url工作,我的意思是使用dirname或pathinfo来获取当前url的目录.但导致host/dir /(主机作为父目录)和host/dir/index.php(host/dir作为父目录,这是正确的)之间的问题
请帮忙我如何获得这些相关照片？
这是我在Apple开发者网站上完成教程后的一个示例Twitter应用程序.但我不知道我做错了什么.
接口:
@interface TWTViewController : UIViewController {
NSString* output;
}
@property (nonatomic, copy) NSString* output;
- (IBAction)doTweet:(id)sender;
- (IBAction)getTimeline:(id)sender;
@property (weak, nonatomic) IBOutlet UILabel *outputLabel;
@property (weak, nonatomic) IBOutlet UIButton *tweetButton;
@end
执行:
@implementation TWTViewController
@synthesize output = _output;
@synthesize outputLabel;
@synthesize tweetButton;
...
- (IBAction)doTweet:(id)sender {
TWTweetComposeViewController *twitter = [[TWTweetComposeViewController alloc] init];
[twitter setInitialText:@"It's really that simple!"];
[twitter addImage:[UIImage imageNamed:@"twitter.png"]];
[self presentViewController:twitter animated:YES completion:nil];
twitter.completionHandler = ^(TWTweetComposeViewControllerResult res) {
if(res == TWTweetComposeViewControllerResultDone) {
UIAlertView* alertView = [[UIAlertView alloc] initWithTitle:@"Success!" …我想从像这样的文件字符串中删除路径:
Root\ToOrganization\Service_b37189b3-8505-4395_Out_BackOffice.xml
我试图找到最后一次出现的"\"的索引,所以我可以使用子串到那里.
但我不能在搜索中使用字符"\".我正在使用"\",但它不起作用......
我正在尝试的代码:
$file = "Root\ToOrganization\Service_b37189b3-8505-4395_Out_BackOffice.xml";
$tmp = rindex($file, "\\");
print $tmp;
我得到的输出:
-1
我能做什么？
from("seda:myqueue?size=2&blockWhenFull=true").process(sleep());
private Processor sleep() {
return new Processor() {
@Override
public void process(Exchange exchange) throws Exception {
String body = exchange.getIn().getBody(String.class);
System.out.println(curTime() + " Going for sleep sleepid=" + body );
Thread.sleep(5000l);
System.out.println(curTime() + " Done sleep sleepid=" + body );
}
};
for (Integer i = 0; i <5; i++) {
Exchange exchange = new DefaultExchange(context);
exchange.setPattern(ExchangePattern.InOnly);
exchange.getIn().setHeader("header", i);
exchange.getIn().setBody(i.toString());
System.out.println("sending msg to seda");
Exchange send = template.send("seda:myqueue",exchange);
System.out.println("done:"+i);
}
“ BlockWhenFull”未确认，即如果大小设置为 2 并且我在循环中发送 3 条消息，正文为“1”、“2”和“3”，那么我只收到“1”和“2”的睡眠消息，我猜即使我将“ BlockWhenFull”设置为 …
我很好奇,我正在用PuTTy 编写C语言,有谁知道我怎么能摆脱这个警告？
警告:忽略'realloc'的返回值,使用属性warn_unused_result声明[-Wunused-result] realloc(strp-> data,nbytes);
^
它想要'警告'我的线的相关代码:
//If the previously allocated size is > 0 then we can reallocate
//otherwise we have to make a new allocation in memory
if(strp->length > 0)
{
realloc(strp->data, nbytes);
}
else
{
*strp = kstralloc(nbytes);
}
提前致谢
尝试连接到Active MQ上的队列时,我收到以下错误消息.
Failed to create route ...because of Failed to resolve endpoint: amq://queue:ROBOMQ.TO.MPM due to: Password must also be provided when using username/password as credentials.
下面的Camel XML中的AMQ bean声明.已经工作了好几个月但现在已经停止了.
<bean id="amq" class="org.apache.activemq.camel.component.ActiveMQComponent">
<property name="brokerURL" value="tcp://127.0.0.1:61616" />
<property name="userName" value="${username}" />
<property name="password" value="${password}" />
</bean>
有任何想法吗？
我希望这段代码永远不会破坏.所以我创建了一个无限循环和一个"goto"到开头,以防它中断.但是,它仍然无法正常工作.
root@xxx:~# cat gmail2.py
import imaplib, re
import os
import time
import socket
socket.setdefaulttimeout(60)
def again():
conn = imaplib.IMAP4_SSL("imap.gmail.com", 993)
conn.login("xx@example.com", "xxx")
while(True):
unreadCount = re.search("UNSEEN (\d+)", conn.status("INBOX", "(UNSEEN)")[1][0]).group(1)
print unreadCount
if int(unreadCount) > 20:
os.system('heroku restart --app sss-xxxx-203')
#os.system('ls')
#print "Restarting server...."
time.sleep(60)
again()
1
Traceback (most recent call last):
File "gmail2.py", line 22, in <module>
again()
File "gmail2.py", line 12, in again
unreadCount = re.search("UNSEEN (\d+)", conn.status("INBOX", "(UNSEEN)")[1][0]).group(1)
File "/usr/lib/python2.6/imaplib.py", line 703, in status
typ, dat = self._simple_command(name, …