以下是代码,我将其作为参考,以了解{}函数中存在的子作用域(或)虚拟作用域(仅)如何影响堆栈帧的结构。
#include <stdio.h>
int main()
{
int main_scope=0; /*Scope and life time of the variable is throughout main*/
{
//From below two statements I assume that there
//is no seperate "stack frame" created for just
//braces {}.So we are free access (scope exists) and
//modify (lifetime exists) the variable "main_scope"
//anywhere within main
main_scope++;
printf("main_scope++:(%d)\n",main_scope);
//I expected this statement to throw an error saying
//"Multiple definition for "main_scope".But it isn't????
int main_scope=2;
printf("Value of redefined main_scope:(%d)\n",main_scope);
}
printf("Finally …Run Code Online (Sandbox Code Playgroud) 当我浏览手册页时shmat.它被描述为API的原始函数是将与其关联的内存段附加shmid到调用进程的地址空间.
我的问题如下.
请考虑以下代码
#include <stdio.h>
#define ROW_SIZE 2
#define COL_SIZE 2
int main()
{
int a[ROW_SIZE][COL_SIZE]={{1,2},{3,4}};
// Base address:Pointer to the first element a 1D array
printf("Base address of array:%p\n",a);
//The value at the base address: should be the address of 1st 1D array
printf("Value at the Base address:%p\n",*a);
return 0;
}
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获得的产出:
Sample Output:
Base address of array:0xbff77434
Value at the Base address:0xbff77434
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不知何故,我无法理解2D数组的基地址的概念和基地址的值,该地址是1D数组的地址相同.请解释.
以下代码导致内存损坏导致崩溃.我假设这是因为delete pTestStateMachine试图删除未在堆中分配的内存.那是对的吗?
如果是这样,是否意味着QStateMachine::addState(QAbstractState * state)必须始终传递动态分配的内存?不幸的是Qt docs并没有指定任何这样的条件.我在这里错过了什么?
class CTestClass
{
public:
QState m_pTestState;
};
int main(int argc, char *argv[])
{
QCoreApplication a(argc, argv);
QStateMachine *pTestStateMachine;
CTestClass TestClass;
pTestStateMachine = new QStateMachine();
pTestStateMachine->addState(&(TestClass.m_pTestState));
pTestStateMachine->setInitialState(&(TestClass.m_pTestState));
pTestStateMachine->start();
pTestStateMachine->stop();
delete pTestStateMachine;
return a.exec();
}
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