小编use*_*194的帖子

我只需要将所选链接显示为已选中并显示指定的div,同时隐藏其他两个.这是jsfiddle:

http://jsfiddle.net/HZ4CZ/1/

为什么第一次点击不起作用,但之后每次点击都会工作？

$(document).ready(function() {
    $('ul#chooseType li a').click(function(e) {   
        $('#active').click(function(){
            $('.activeDiv').removeClass('show_hide');
            $('.inactiveDiv').addClass('show_hide');
            $('.thirdMenuDiv').addClass('show_hide');
            $('#active').addClass('selected');
            $('#inactive').removeClass('selected');
            $('#thirdMenu').removeClass('selected');
        });
        $('#inactive').click(function(){
            $('.activeDiv').addClass('show_hide');
            $('.inactiveDiv').removeClass('show_hide');
            $('.thirdMenuDiv').addClass('show_hide');
            $('#active').removeClass('selected');
            $('#inactive').addClass('selected');
            $('#thirdMenu').removeClass('selected');
        });
        $('#thirdMenu').click(function(){
            $('.activeDiv').addClass('show_hide');
            $('.inactiveDiv').addClass('show_hide');
            $('.thirdMenuDiv').removeClass('show_hide');
            $('#active').removeClass('selected');
            $('#inactive').removeClass('selected');
            $('#thirdMenu').addClass('selected');
        });

    });
});

我希望我的查询返回这样的内容:

n.property1? OR n.property2? as columnName

用例是我在一个查询中返回两个不同的节点原型,一个节点类型没有property2而另一个没有property1,但实现了相同的目的,我需要它们在相同的列名下返回.(例如,如果一个人只能输入家庭电话号码(n.home)或手机号码(n.cell),但您希望它作为电话返回(n.home？或n.cell？作为电话) ).)

有没有办法实现这个目标？

如何以零计数返回此报表？任何时候我想要返回的任何字段等于零，整个查询都会返回 null？我一直遇到这个问题，我迫切需要一个解决方案。

START bp=node({startnodeid}) 
WITH bp 
MATCH (bp)<-[r1?:VIEWED_PROFILE]-() 
WHERE r1.timestamp > {weekStart} AND r1.timestamp < {firstDay} 
WITH count(r1) AS dayOne, bp 
MATCH (bp)<-[r2?:VIEWED_PROFILE]-() 
WHERE r2.timestamp > {firstDay} AND r2.timestamp < {secondDay}
WITH count(r2) AS dayTwo, dayOne, bp 
MATCH (bp)<-[r3?:VIEWED_PROFILE]-() 
WHERE r3.timestamp > {secondDay} AND r3.timestamp < {thirdDay} 
WITH count(r3) AS dayThree, dayTwo, dayOne, bp 
MATCH (bp)<-[r4?:VIEWED_PROFILE]-() 
WHERE r4.timestamp > {thirdDay} AND r4.timestamp < {fourthDay}
WITH count(r4) AS dayFour, dayThree, dayTwo, dayOne, bp 
MATCH (bp)<-[r5?:VIEWED_PROFILE]-() 
WHERE r5.timestamp > {fourthDay} AND r5.timestamp …