谁能告诉我如何在 Vim 中更改 Python 颜色。我已经看到以下语法,但我不确定如何使其永久化。
:hi pythonComment ctermfg=2 gui=italic guifg=#408010
Run Code Online (Sandbox Code Playgroud) 我有一些扩展行的代码.该表有每个td的填充.哪个没问题,但折叠后的表格仍显示此填充,
http://jsfiddle.net/0Lh5ozyb/55/
下面是jquery
$('tr.parent')
.css("cursor", "pointer")
.click(function () {
var $children = $(this).nextUntil( $('tr').not('[class^=child-]') );
$children.find('td > div').slideToggle();
});
$('tr[class^=child-]').find('td > div').hide();
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下面是HTML
<table class="table">
<tr class="parent" id="row1">
<td><div>People</div></td>
<td><div>Click to Expand</div></td>
<td><div>N/A</div></td>
</tr>
<tr class="child-row1-1">
<td><div>Eve</div></td>
<td><div>Jackson</div></td>
<td><div>94</div></td>
</tr>
<tr class="child-row1-2">
<td><div>John</div></td>
<td><div>Doe</div></td>
<td><div>80</div></td>
</tr>
<tr class="parent" id="row2">
<td><div>People</div></td>
<td><div>Click to Expand</div></td>
<td><div>N/A</div></td>
</tr>
<tr class="child-row2-1">
<td><div>Eve</div></td>
<td><div>Jackson</div></td>
<td><div>94</div></td>
</tr>
<tr class="child-row2-1">
<td><div>John</div></td>
<td><div>Doe</div></td>
<td><div>80</div></td>
</tr>
<tr class="parent" id="row3">
<td><div>People</div></td>
<td><div>Click to Expand</div></td>
<td><div>N/A</div></td>
</tr>
<tr class="child-row3-1"> …Run Code Online (Sandbox Code Playgroud) 我有以下model.py.
from django.db import models
class Address(models.Model):
addr = models.CharField(max_length=150)
def __unicode__(self):
return u'%s' % (self.addr)
class Anniversary(models.Model):
date = models.DateField()
def __unicode__(self):
return u'%s' % (self.date)
class Person(models.Model):
name = models.CharField(max_length=50)
birthday = models.DateField()
anniversary = models.ForeignKey(Anniversary)
address = models.ForeignKey(Address)
def __unicode__(self):
return u'%s %s %s %s' % (self.name, self.birthday, self.anniversary, self.address)
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我想将所有条目的内容打印到我的模板中.但按出生日期与当前日期排序.即最近的第一个然后是名字.做这个的最好方式是什么.我应该先将它排序然后将其附加到列表或字典中吗?
任何指针都会很棒.
谢谢,
我有一个apache实例,我有以下内容
WSGIPythonPath /production/somelocation/django12/lib/python2.4/site-packages/
<VirtualHost 192.168.1.1:443>
WSGIScriptAlias / /opt/project.wsgi
.....
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我的Django 1.5 app apache配置看起来像,
WSGIPythonPath /production/somelocation/django15/lib/python2.7/site-packages/
<VirtualHost 192.168.1.2:443>
....
WSGIScriptAlias / /opt/project2.wsgi
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我的/opt/project.wsgi看起来像
import os
import sys
# django1.2 virtualenv
import site
site.addsitedir("/production/somelocation/django12/lib/python2.4/site-packages")
.....
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但是,当我去网站时,我仍然得到我的默认django(1.5)实例.我错过了什么?
我目前有一个简单的AJAX页面,我通过AJAX提交数据,然后通过显示在屏幕上的AJAX接收响应.当服务器正在处理响应时,我想创建一个进度条.我的想法是我可以将多个ajax更新发送回客户端,其中包含客户端可以转换为进度条(即通过引导程序)的进度,直到发送最终响应.
是否可以从单个AJAX请求发送多个AJAX响应,或者执行此操作的最佳方法是什么.
谢谢,
使用Django REST框架通过REST查询Django时出现错误,
File "/folder/pythonenv/project/lib/python2.7/site-packages/rest_framework/serializers.py", line 241, in get_fields
assert isinstance(self.opts.fields, (list, tuple)), '`fields` must be a list or tuple'
AssertionError: `fields` must be a list or tuple
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我的设置是......
settings.py
THIRD_PARTY_APPS = (
'south', # Database migration helpers:
'crispy_forms', # Form layouts
'rest_framework',
)
REST_FRAMEWORK = {
'DEFAULT_PERMISSION_CLASSES': (
'rest_framework.permissions.AllowAny',
)
}
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意见
from django.shortcuts import render
from rest_framework import viewsets
from quickstart.serializers import from quickstart.serializers import TicketInputSerializer
from models import Abc
class TicketInputViewSet(viewsets.ModelViewSet):
queryset = Abc.objects.all()
serializer_class = TicketInputSerializer
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urls.py …
我试图创建一个芹菜文件并运行它..
celery -A myapp worker -l info
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但是我得到了错误,
File "/production/pythonenv/project/lib/python2.7/site-packages/configurations/base.py", line 30, in __new__
raise ImproperlyConfigured(install_failure)
django.core.exceptions.ImproperlyConfigured: django-configurations settings importer wasn't correctly installed. Please use one of the starter functions to install it as mentioned in the docs: http://django-configurations.readthedocs.org/
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这是配置/文件,
树
(通过'tree myapp/config /'从项目rool运行)
config/
|-- __init__.py
|-- __init__.pyc
|-- celery.py
|-- settings.py
|-- urls.py
|-- wsgi.py
myapp/
|-- __init__.py
|-- __init__.pyc
|-- celery.py
|-- helper.py
|-- models.pyc
|-- serializers.py
|-- views.py
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celery.py
from __future__ import absolute_import
import os,sys,
from …Run Code Online (Sandbox Code Playgroud) 有谁知道如何在 Python 中使用 re.sub 和列表推导式。
我使用以下内容,
>>> a = ["N","!","1","abc"]
>>> [(re.sub(r'(h|N|!|N|1)', r"'\033[91m'\g<1>'\033[0m'", 'x')) for x in a]
['x', 'x', 'x', 'x']
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正如您所看到的,我只将 x 作为列表元素返回。
谢谢,
如何访问 Google Compute Engine 虚拟机实例的控制台?
现在我几乎只使用 Python Rich 实现来进行打印。IE from rich import print。
有没有办法用 Rich 实现替换内置的 Python 打印,而不是将其添加到我编写的每个脚本中?