小编Ale*_*lex的帖子

我正在尝试编写一个实现UserType的类来处理Hibernate/JPA中的数组.我使用以下帖子 使用hibernate和Hibernate/JPA/HSQL 映射postgres数组:如何为用户类型ARRAY创建Dialect映射以构建解决方案,但我无法使其工作.我创建了一个新的Spring Roo项目来测试它.以下是不同的文件(所有java类都位于包测试中):

• persistence.xml中

  <?xml version="1.0" encoding="UTF-8" standalone="no"?>
  <persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" version="2.0" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
    <persistence-unit name="persistenceUnit" transaction-type="RESOURCE_LOCAL">
      <provider>org.hibernate.ejb.HibernatePersistence</provider>
      <properties>
      <!--  <property name="hibernate.dialect" value="org.hibernate.dialect.PostgreSQLDialect"/> -->
      <property name="hibernate.dialect" value="test.PostgreSQLDialectArray"/>
      <!-- value="create" to build a new database on each run; value="update" to modify an existing database; value="create-drop" means the same as "create" but also drops tables when Hibernate closes; value="validate" makes no changes to the database -->
      <property name="hibernate.hbm2ddl.auto" value="create"/>
      <property name="hibernate.ejb.naming_strategy" value="org.hibernate.cfg.ImprovedNamingStrategy"/>
      <property name="hibernate.connection.charSet" value="UTF-8"/>
      <!-- Uncomment …

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