小编Ili*_*Ili的帖子

我正在尝试创建一个按钮，onClick 将为您提供放置链接的选项，然后该链接必须在文本字段中显示为标签。到目前为止，我设法添加并显示纯文本，但我不知道如何将其转换为标签。

// Link function
  const addLinkFn = (editorState, link) => {
    const contentState = editorState.getCurrentContent();
    const contentStateWithEntity = contentState.createEntity(
      "LINK",
      "IMMUTABLE",
      { url: link }
    );
    const entityKey = contentStateWithEntity.getLastCreatedEntityKey();
    const newEditorState = EditorState.set(editorState, {
      currentContent: contentStateWithEntity,
    });
    return AtomicBlockUtils.insertAtomicBlock(newEditorState, entityKey, link);
  };

  const onAddLink = () => {
    let link = window.prompt("Add link http:// ");
    const newEditorState = addLinkFn(editorState, link);
    setEditorState(newEditorState);
  };

我知道在某个地方我必须有一个像这样的“装饰器”和“策略”：

const linkStrategy = (contentBlock, callback, contentState) => {
  contentBlock.findEntityRanges((character) => {
    const entityKey = character.getEntity(); …

我正在创建 RTS 游戏，其中一项功能是构建不同类型的建筑物。我发现了很多重复，我想在辅助方法中提取它，但问题是每个建筑物都是不同的对象，它们从主建筑物类中吸收了一些属性。

构建方法如下所示：

  public static void buildDockyard(Base base) {
    if (Validator.checkForBuilding(base, "Dockyard")) {
       throw new IllegalStateException("Dockyard is already build");
     }
    Dockyard dockyard = new Dockyard("Dockyard");
    int requiredPower = dockyard.requiredResource("power");
    int requiredStardust = dockyard.requiredResource("stardust");
    int requiredPopulation = dockyard.requiredResource("population");

    Validator.checkResource(base, requiredPower, requiredStardust, requiredPopulation);
    updateResourceAfterBuild(base, requiredPower, requiredStardust, requiredPopulation);
    dockyard.setCompleteTime(dockyard.requiredResource("time"));
    base.getBuildings().add(dockyard);
  }

  public static void buildHotel(Base base) {
    if (Validator.checkForBuilding(base, "Space Hotel")) {
      throw new IllegalStateException("Space Hotel is already build");
    }

    SpaceHotel spaceHotel = new SpaceHotel("Space Hotel");
    int requiredPower = spaceHotel.requiredResource("power");
    int requiredStardust …