当我在chrome中运行我的页面时,我收到此错误"未捕获的syntaxerror意外令牌U".在Firefox中,我得到了"JSON.parse:意外的角色".我从php文件返回json数据,返回的json字符串有效.我用http://jsonlint.com/检查了它.任何帮助将不胜感激...谢谢.
这是返回的JSON字符串
[
["1","Pan Africa Market","\"1521 1st Ave, Seattle, WA\"","47.608941","-122.340145","restaurant"],
["2","The Melting Pot","14 Mercer St, Seattle, WA","47.624562","-122.356442","restaurant"],
["3","Ipanema Grill","1225 1st Ave, Seattle, WA","47.606366","-122.337656","restaurant"],
["4","Sake House","230 1st Ave, Seattle, WA","47.612825","-122.34567","bar"],
["5","Crab Pot","1301 Alaskan Way, Seattle, WA","47.605961","-122.34036","restaurant"],
["6","Mexican Kitchen","2234 2nd Ave, Seattle,WA","47.613975","-122.345467","bar"],
["7","Wingdome","1416 E Olive Way, Seattle, WA","47.617215","-122.326584","bar"],
["8","Piroshky Piroshky","1908 Pike pl, Seattle, WA","47.610127","-122.342838","restaurant"]
]
请问清空列表最有效的方法是什么？
我有一个名单a = [1,2,3].要删除我经常写的列表内容a = [ ].我遇到了一个名为python的函数del.我想知道del a [:]我和之间是否存在差异.
让我们说 Zaptoit:685158:zaptoit@hotmail.com
你怎么分裂所以它只剩下 685158:zaptoit@hotmail.com
在Ember.js中创建"标准"crud资源时,索引路由和"主"路由之间有什么区别？
例如,用户资源:
// app.router.js
Router.map(function() {
this.resource('users', function() {
this.route('new');
this.route('show', { path: '/:user_id'});
this.route('edit', { path: '/:user_id/edit'});
});
});
哪条路线应包含以下"主"模型钩子？
// app/routes/users/index.js OR app/routes/users.js?
export default Ember.Route.extend({
model: function() {
return this.store.find('user');
}
});
换句话说,我应该使用UsersRoute还是UsersIndexRoute？我觉得这很混乱.任何帮助是极大的赞赏.
当我运行makemigrations命令时,我收到此错误:
Traceback (most recent call last):
...
django.db.migrations.exceptions.NodeNotFoundError: Migration products.0002_auto_20160618_1143 dependencies reference nonexistent parent node (u'products', u'0001_initial')
如何删除表数据,但不删除表列名？
ID | NAME | AGE | ADDRESS | SALARY |
+----+----------+-----+-----------+----------+
| 1 | Ramesh | 32 | Ahmedabad | 2000.00 |
| 2 | Khilan | 25 | Delhi | 1500.00 |
| 3 | kaushik | 23 | Kota | 2000.00 |
| 4 | Chaitali | 25 | Mumbai | 6500.00 |
| 5 | Hardik | 27 | Bhopal | 8500.00 |
| 6 | Komal | 22 | MP | 4500.00 |
| 7 …我在递归中遇到了这个问题.我无法弄清楚它是如何工作的.我理解递归的基础知识但这完全让我感到困惑.请帮忙.
main() {
foo(3);
}
void foo(int x) {
if (x >= 1) {
foo(--x);
printf("%d", x);
foo(--x);
}
}
我认为这个程序不打印任何东西,但它打印0120.
是不是第一次调用foo( - 3)即foo(2)跳转到函数的开头并重复直到3递减到0？
请解释这是如何工作的.
我有以下的代码和变量,我想找到什么样的变量a,a1,a2,b,b1,和b2参考代码已经执行之后.
def do_something(a, b):
a.insert(0, "z")
b = ["z"] + b
a = ["a", "b", "c"]
a1 = a
a2 = a[:]
b = ["a", "b", "c"]
b1 = b
b2 = b[:]
do_something(a, b)
我尝试的解决方案如下:
a = ["z", "a", "b", "c"]
a1 = ["a", "b", "c"]
a2 = ["a", "b", "c"]
b = ["z" "a", "b", "c"]
b1 = ["a", "b", "c"]
b2 = ["a", "b", "c"] …我正在使用Flask和Flask-Mail构建一个简单的联系页面.我按照本教程构建了应用程序 - 添加联系页面 - 现在当我尝试发送消息时,我收到了错误消息gaierror: [Errno -2] Name or service not known.我一直在谷歌搜索错误一段时间,并没有在线找到任何类似的例子.我甚至无法弄清楚它找不到的名称或服务.
回溯页面将让我展开一行并执行一些Python代码.它提供了一个dump()函数,它将向我显示所有变量,并且可以在对象上调用以查看其信息(如果这将有所帮助).
routes.py:
from forms import ContactForm
from flask.ext.mail import Message, Mail
mail = Mail()
app = Flask(__name__)
app.secret_key = 'development key'
app.config['MAIL_SERVER'] = 'smtp.google.com'
app.config['MAIL_PORT'] = 465
app.config['MAIL_USE_SSL'] = True
app.config['MAIL_USERNAME'] = 'email'
app.config['MAIL_PASSWORD'] = 'password'
mail.init_app(app)
@app.route('/contact', methods=['GET', 'POST'])
def contact():
form = ContactForm()
if request.method == 'POST':
if not form.validate():
表格:
from flask.ext.wtf import Form, validators
from wtforms.fields import TextField, TextAreaField, SubmitField …我正在尝试编译一个程序(python2.7),但无论我做什么,我都会遇到这个错误:
C:/Python27/tcl/tk8.5/tk.tcl: version conflict for package "Tk": have 8.5.2, need exactly 8.5.15
version conflict for package "Tk": have 8.5.2, need exactly 8.5.15
while executing
"package require -exact Tk 8.5.15"
(file "C:/Python27/tcl/tk8.5/tk.tcl" line 18)
invoked from within
"source C:/Python27/tcl/tk8.5/tk.tcl"
("uplevel" body line 1)
invoked from within
"uplevel #0 [list source $file]"
这可能意味着tk安装不正确.
有人可以向我解释一下这里有什么问题吗？