有一个PostgreSQL SQL SELECT结果.我需要将行划分为五分位数并将quintil值更新为特定行.
是否有可能在SELECT中执行此要求而无需在应用程序中执行此操作?当我需要选择数据到应用程序并从PostgreSQL服务器中排名时,我想避免这种情况.
数据示例 - 第一列是值,第二列是quintil
4859 - 5 4569 - 5 4125 - 4 3986 - 4 3852 - 3 3562 - 3 3452 - 2 3269 - 2 3168 - 1 3058 - 1
谢谢.
当独立的Spring Boot应用程序@Asynch中带@Service注释的类中的方法不能异步运行时,我该怎么办?
当我运行它时,直接从工作中的主类(带@SpringBootApplication注释)直接使用相同的方法。例:
主班
@SpringBootApplication
@EnableAsync
public class Application implements CommandLineRunner {
@Override
public void run(String... args) throws Exception {
// here when I call downloadAnSave() it runs asynchronously...
// but when I cal downloadAnSave() via downloadAllImages() it does not run asynchronously...
}
}
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和我的服务类(这里的异步行为不起作用):
@EnableAsync
@Service
public class ImageProcessorService implements IIMageProcessorService {
public void downloadAllImages(Run lastRun){
// this method calls downloadAnSave() in loop and should run asynchronously....
}
@Async
@Override
public …Run Code Online (Sandbox Code Playgroud) 我想在我所需的输入字段之前的标签中添加一个CSS类.我可以通过JavaScript实现,但我想在CakePHP中实现.
是否有一些选项可以告诉CakePHP自动执行此操作?
我试图在服务层中存根一个方法来测试另一个对象:
@SpringBootTest
@RunWith(JUnitPlatform.class)
class WorkreportCrudFacadeTest {
private static Logger LOGGER = LogManager.getLogger(WorkreportCrudFacadeTest.class);
@Test
public void detailTest() {
final AccessRightsService ars = Mockito.mock(AccessRightsService.class);
final SystemPriceSettingService spss = Mockito.mock(SystemPriceSettingService.class);
final WorkreportActivityRepository wrar = Mockito.mock(WorkreportActivityRepository.class);
final WorkreportRepository wrr = Mockito.mock(WorkreportRepository.class);
final DomainObjectTools dot = Mockito.mock(DomainObjectTools.class);
final ApplicationEventPublisher aep = Mockito.mock(ApplicationEventPublisher.class);
Mockito.when(ars.hasEmployeeRightsToWorkReport(
ArgumentMatchers.any(Employee.class), ArgumentMatchers.any(Workreport.class)
)
).thenReturn(true);
final WorkreportCrudFacade s = new WorkreportCrudFacade(ars, spss, wrar, wrr, dot, aep);
final EmployeeId employeeId = new EmployeeId(154149756298300L);
final WorkreportId workreportId = new WorkreportId(154149757395700L);
final Workreport detail = s.detail(workreportId, …Run Code Online (Sandbox Code Playgroud) 客户迫使我们使用JdbcTemplate而不是Spring Data Jpa来开发Spring项目。但是,该应用程序在响应速度和传递方面并不关键(它是客户端最终用户的内部Web应用程序)。我们想使用Spring Data Jpa。
问题:是否有一些客观的理由使用JdbcTemplate是因为应用程序的速度快?从我的角度来看,会有不同的瓶颈。
我遇到了一个trim('/','/musla-ktora-lieci/');返回空字符串的问题.它的工作原理相同的方式与所有装饰功能- trim(),ltrim()和rtrim().
PHP:
PHP 5.5.20 (cli) (built: Feb 25 2015 23:30:53)
Copyright (c) 1997-2014 The PHP Group
Zend Engine v2.5.0, Copyright (c) 1998-2014 Zend Technologies
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我究竟做错了什么?
spring ×2
asynchronous ×1
cakephp ×1
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java ×1
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performance ×1
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