小编xsi*_*aul的帖子

我是 Spring 框架的新手。目前我尝试集成 cron 作业服务。

我将一个服务类定义为：

package com.test.cron;
@Service
public class CronJob {
    protected static final Logger logger = Logger.getLogger(PasswordRemindFlusher.class);

    @Scheduled(cron="0 0/2 * * * ?")
    public void demoServiceMethod()
    {

        logger.debug("Cron job started.");
    }
}

然后我在servlet配置中定义：

<context:component-scan base-package="com.test.cron" />

弹簧servlet.xml：

<?xml  version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context"
    xmlns:mvc="http://www.springframework.org/schema/mvc"
    xsi:schemaLocation="http://www.springframework.org/schema/beans 
    http://www.springframework.org/schema/beans/spring-beans.xsd
    http://www.springframework.org/schema/context 
    http://www.springframework.org/schema/context/spring-context.xsd
    http://www.springframework.org/schema/mvc 
    http://www.springframework.org/schema/mvc/spring-mvc.xsd
    http://www.springframework.org/schema/task 
    http://www.springframework.org/schema/task/spring-task-3.0.xsd">

<context:annotation-config />

<context:component-scan base-package="com.test.cron" />
<task:annotation-driven />
</beans>

网页.xml：

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
    version="2.5">
    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/spring-servlet.xml</param-value>
    </context-param>
    <listener> …