小编sgi*_*len的帖子

我需要将8位IplImage转换为32位IplImage.使用来自整个网络的文档,我尝试了以下方法:

// general code
img2 = cvCreateImage(cvSize(img->width, img->height), 32, 3);
int height    = img->height;
int width     = img->width;
int channels  = img->nChannels;
int step1     = img->widthStep;
int step2     = img2->widthStep;
int depth1    = img->depth;
int depth2    = img2->depth;
uchar *data1   = (uchar *)img->imageData;
uchar *data2   = (uchar *)img2->imageData;

for(h=0;h<height;h++) for(w=0;w<width;w++) for(c=0;c<channels;c++) {
   // attempt code...
}

// attempt one
// result: white image, two red spots which appear in the original image too.
// this is the closest result, what's …

我正在尝试编写一个程序,它接受一个SDL_Surface,将其转换为一个IplImage,使用cvBlobsLib查找blob,将blob绘制为图像上的斑点,然后将输出转换IplImage回SDL_Surface.

我差点儿完成了:只将IplImage背部转换为SDL_Surface尚未完成.该IplImage具有3个图像通道,每像素8位.我想我可以使用两个电话:

SDL_Surface *SDL_CreateRGBSurface(Uint32 flags, int width, int height, int depth, Uint32 Rmask, Uint32 Gmask, Uint32 Bmask, Uint32 Amask);
SDL_Surface *SDL_CreateRGBSurfaceFrom(void *pixels, int width, int height, int depth, int pitch, Uint32 Rmask, Uint32 Gmask, Uint32 Bmask, Uint32 Amask);

我正在尝试SDL_CreateRGBsurfaceFrom.但是,我不知道音高,Rmask,Gmask和Bmask的正确值是什么.(Amask为0,因为没有alpha通道.)

有人可以通过解释如何做到这一点来帮助我吗？

谢谢!

编辑:例如,这是我尝试使用的代码:

SDL_Surface *ipl_to_surface (IplImage *opencvimg)
{
    int pitch = opencvimg->nChannels*opencvimg->width;
    printf("Depth %d, nChannels %d, pitch %d\n", opencvimg->depth,
                    opencvimg->nChannels, pitch);
    SDL_Surface *surface = SDL_CreateRGBSurfaceFrom((void*)opencvimg->imageData,
                    opencvimg->width, …