小编sam*_*shi的帖子

在我的wp项目中,我使用Assently进行电子签名实现.虽然我有一个帐户并创建了一个由用户填写的pdf表单文件,但我无法进行一些操作.我发现文件不清楚.此外,我不清楚需要做什么,以便用户将被显示表单来处理交易.

因此,任何有助于继续前进的帮助/建议都表示赞赏.

我基于同意laravel尝试了以下.但它要求我登录.什么是错误？码:

define('ASSENTLY_DEBUG', true);
define('ASSENTLY_KEY', 'key');
define('ASSENTLY_SECRET', 'secret-generated');

include_once('assently/Assently.php');
$assently = new Assently();
$assently->authenticate(ASSENTLY_KEY, ASSENTLY_SECRET);

$url = 'https://test.assently.com/api/v2/createcasefromtemplate';
$default = array(
    'Id' => '5a0e0869-'.rand(1111, 9999).'-4b79-'.rand(1111, 9999).'-466ea5cca5ce'
);
$data = array(
    'auth' => $assently->auth(),
    'templateId' => '0e004e2b-b192-4ce2-8f47-d7a4576d7df6',
    'newCaseId' => '5a0e0869-'.rand(1111, 9999).'-4b79-'.rand(1111, 9999).'-466ea5cca5ce',
    'agentUsername' => ''
);

$data = array(
        'json' => $data
    );
    $options = array(
        'http' => array(
            'header'  => "Content-type: application/json; charset=utf-8\r\n",
            'method'  => 'POST',
            'content' => http_build_query($data)
        )
    );
    $context  = stream_context_create($options);
    $result …

我试图添加两个十进制值,但返回的总和是纯整数.怎么了？我找不到它.欢迎任何帮助.

jQuery(".delivery-method #ship_select").change(function(){
    var cost = jQuery(this).val(); 
    jQuery("#delivery_cost").val(cost); //returns 20.00
    var tot = parseInt(cost) + parseInt(total); //total returns 71.96
});

使用代码我只得到91而不是91.96

我有自己的工作经验,可以通过输入动态添加组织名称,部门名称,职位和持续时间.

<tr>
    <td><span class="serial_no">1</span></td>
    <td><input type="text" name="organization[]" size="50"/></td>
    <td><input type="text" name="department[]" size="50"></td>
    <td><input type="text" name="positions[]" size="40"></td>
    <td><input type="text" name="duration[]"></td>
</tr>

在CI中验证时,我执行了以下操作:

$organization = $this->input->post('organization');
$department   = $this->input->post('department');
$positions    = $this->input->post('positions');
$duration     = $this->input->post('duration');

//printr($organization);
for($i = 0; $i < count($organization); $i++) 
{
    $org = $organization[$i];
    $dept = $department[$i];
    $pos = $positions[$i];
    $dura = $duration[$i];

    $this->form_validation->set_rules($org, "Organization", "trim|xss_clean|max_length[1]");
    $this->form_validation->set_rules($dept, "Department", "trim|xss_clean|max_length[50]");
    $this->form_validation->set_rules($pos, "Position", "trim|xss_clean|max_length[40]");
    $this->form_validation->set_rules($dura, "Duration", "trim|xss_clean|integer");
}

并显示错误:

<?php
    echo form_error("organization[]");
    echo form_error("department[]"); 
    echo form_error("positions[]"); 
    echo form_error("duration[]");
?> 

现在的问题是它不会将持续时间验证为整数.即使我放了一些随机的字母字符,它也不会显示错误.

当我验证如下: …

有谁知道如何集成Sharepoint和Php.我正在尝试开发可以连接到Sharepoint的php应用程序.特别是因为基本上我是网站开发人员,我希望我的所有网站都与Sharepoint连接.所以,我只想创建Php应用程序,使其适用于所有网站.我不知道是否可能,但我想尝试但不知道如何继续.

任何想法/建议都是受欢迎的.

提前致谢.

我在引导模式中使用 ckeditor。ckeditor 中的数据应在 ajax 调用后动态加载。我无法在 ckeditor 中加载数据。代码 ：

<div class="modal fade" id="exampleModal" tabindex="-1" role="dialog" aria-labelledby="exampleModalLabel" aria-hidden="true">
      <div class="modal-dialog">
        <div class="modal-content">
          <div class="modal-header">
            <button type="button" class="close" data-dismiss="modal" aria-label="Close"><span aria-hidden="true">&times;</span></button>
            <h4 class="modal-title" id="exampleModalLabel">Thank you Message</h4>
          </div>
          <div class="modal-body">
            <form>
              <div class="form-group">
                <label for="recipient-name" class="control-label">Recipient:</label>
                <input type="text" class="form-control" id="recipient-name">
              </div>
              <div class="form-group">
                <label for="recipient-name" class="control-label">Subject:</label>
                <input type="text" class="form-control" id="subject">
              </div>
              <div class="form-group">
                <label for="message-text" class="control-label">Message:</label>
                <?php $ckeditor->editor('message', '', array('id'=>'editor1')); ?>
              </div>
            </form>
          </div>
          <div class="modal-footer">
            <button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
            <button type="button" class="btn …

我在登录页面中使用记住选项.我认为我做得对,但在退出时我无法取消设置cookie变量.我正在使用CI但是我使用的是cookie我使用原生cookie.我做错了什么我的代码:在登录控制器中:

function index(){
if(isset($_COOKIE['remember_me'])){
  redirect('index');
}elseif($this->input->post()){
  $username = $this->input->post('username');
  $password = $this->input->post('password');
  $remember = $this->input->post('remember');
  if($remember){
      $time = time()+60*60*24*365;
      setcookie('remember_me', $username , $time);
  }
  $this->session->set_userdata('user_name', $user_name);
  $this->session->set_userdata('full_name', $full_name);
  $this->session->set_userdata('server', $server->exchange_server);
  redirect('index');
}else{
  $this->load->view('login');
}
}
function logout(){
 $this->session->unset_userdata('user_name');
 $this->session->unset_userdata('full_name');
 $this->session->unset_userdata('server');
 $data['login'] = 'Logout Successfully.';
 $data['class'] = 'success';
 $this->session->set_flashdata($data);
/* To unset cookie i tried following different approach but to no avail*/
setcookie('remember_me');
setcookie('remember_me', '', $time()-60*60*24*365);
setcookie('remember_me', false);
unset($_COOKIE['remember_me']);
 redirect('login');
}

但无济于事.我只是不能取消设置cookie,当用户检查过时,请记住我选项trys注销它没有发生.欢迎任何帮助/建议.谢谢

我不知道是什么问题,但我使用jquery插件进行cookie删除{ https://github.com/carhartl/jquery-cookie }.我包括jquery.cookie.js然后在注销时单击我删除了cookie设置为$ .removeCookie('remember_me')

我DATE_FORMAT在数据库中使用mysql 作为特定的日期时间.Mysql查询是:

$this->db->select('remarks_date, DATE('remarks_date') AS rem_dateonly, DATE_FORMAT('remarks_date', '%y-%m-%d %h:%i') AS day_hour_mins, DATE_FORMAT('remarks_date', '%y-%m-%d %h') AS day_hour, tbl_complain_detail.complain_summary, tbl_complain_detail.id, tbl_complain_detail.complain_no, tbl_complain_detail.created_by, escalation_status, tbl_admin_user.first_name, tbl_admin_user.middle_name, tbl_admin_user.last_name');
$this->db->where('tbl_complain_remarks.status', 'Time Extension');
$this->db->where('tbl_complain_detail.status !=', 'Completed');
$this->db->where('tbl_complain_detail.time_extension_status', '1');
$this->db->join('tbl_complain_remarks', 'tbl_complain_remarks.complain_id = tbl_complain_detail.id');
$this->db->join('tbl_admin_user', 'tbl_admin_user.id = tbl_complain_detail.user_id');
$result2 = $this->db->get('tbl_complain_detail')->result();

我在这里得到错误

PHP Parse error: syntax error, unexpected T_STRING in select line

而且它没有采取%.为什么？

难道我做错了什么？任何帮助/建议将不胜感激.

下面我有一年的下拉菜单.

<select name="from_year" class="col-md-4 form-control" id="from_year">
    <option value="0">Select Year</option>
    <option value="2010">2010</option>
    <option value="2011">2011</option>
    <option value="2012">2012</option>
    <option value="2013">2013</option>
    <option value="2014">2014</option>
    <option selected="selected" value="2015">2015</option>
    <option value="2016">2016</option>
    <option value="2017">2017</option>
    <option value="2018">2018</option>
    <option value="2019">2019</option>
    <option value="2020">2020</option>
</select>

现在从ajax电话我得到一年说2016年.现在我想禁用低于2016年的所有选项.我试过以下:

$('select#from_year option:lt('+payment_date[1]+')').prop("disabled", true);

...在哪里payment_date[1] = 2016,但无济于事.

难道我做错了什么.欢迎任何帮助/建议.

我正在尝试创建一个带有方向的谷歌地图,并使用折线.但我得到上面的控制台错误,我只是无法得到这里的问题.代码:

<script src="https://maps.googleapis.com/maps/api/js?sensor=false" type="text/javascript"></script>
var marker;
var infowindow;
var labels = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ';
var labelIndex = 0;
var markers = {};
var currentId = 0;
var uniqueId = function() {
    return ++currentId;
}
var edit = 0;
var direction = '';
var linecordinates = [];
var map;
var sortorder = 0;
var latest_marker;
var latest_latlng;
var lineSymbol;
var flightPath;
var line = [];

var saved_locations = $("#hidden_lat_long").val();
// saved_locations = [{"label":1,"lat":"27.7233","long":"85.2783"},{"label":2,"lat":"27.7625","long":"85.3411"},{"label":3,"lat":"27.7056","long":"85.4166"},{"label":4,"lat":"27.6704","long":"85.3209"}]

function initialize() {
    lineSymbol = {
        path: google.maps.SymbolPath.FORWARD_CLOSED_ARROW
    };
    /* …