小编use*_*236的帖子

当我点击UITextField时如何显示UIPickerView?

我从互联网上找到了很多示例代码,但也没有用....任何人都可以告诉我下面编码的错误是什么?非常感谢.SOS

//我的商店屏幕
http://imageupload.org/en/file/209300/03.jpg.html

//This is PickerViewTest.h

@interface InputRound : UIViewController<UITextFieldDelegate>
{
    UIPickerView *pvPickerTest;
    NSMutableArray *aryMaster;
}

@property (nonatomic, retain) IBOutlet UIPickerView *pvPickerTest; 
@property (nonatomic, retain) NSMutableArray *aryMaster;

@end


//This is PickerViewTest.m

@interface InputRound ()

@end

@implementation PickerViewTest

@synthesize pvPickerTest, aryMaster;

-(id)initWithNibName:(NSString *)nibNameOrNil bundle:(NSBundle *)nibBundleOrNil
{
    self = [super initWithNibName:nibNameOrNil bundle:nibBundleOrNil];
    if (self) {
        // Custom initialization
    }
    return self;
}

-(void)viewDidLoad
{
    [super viewDidLoad];
    // Do any additional setup after loading the view.

    aryMaster = [[NSMutableArray alloc] init];

    [aryMaster addObject:@"User01"]; …
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cocoa-touch uipickerview uitextfield ios

3
推荐指数
1
解决办法
8833
查看次数

插入值与组合标识列

Let's say I have this table with the identity column pkid, how can I generate the cust_num as VIP000000 + <pkid> when inserting a record like this?

pkid cust_name cust_num
1 Tom VIP0000001
2 May VIP0000002
10 John VIP0000010
CREATE TABLE [dbo].[tbl01]
(
    [pkid] [numeric](9, 0) IDENTITY(1,1) NOT NULL,
    [cust_name] [varchar](50) NOT NULL,
    [cust_num] [varchar](20) NOT NULL
) ON [PRIMARY]
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sql sql-server

0
推荐指数
1
解决办法
136
查看次数

为什么这些字符串不相等?

我有以下编码,我确保如果条件为TRUE,但我无法进入它.我通过使用NSLog将步骤前后的值和长度写入if语句证明它,两者都等于"test"和length = 4,任何人都可以解决我的问题?

请看下面链接哪个是我的帽子屏幕,请帮忙,谢谢!!!!

http://postimage.org/image/rvtxcq1g1/

NSLog(@"Before value=%@, lenght=%i", txtMaster.text, [txtMaster.text length]);

if (txtMaster.text == @"test")
{
   NSLog(@"%@\n", @"Success");
}

NSLog(@"After value=%@, lenght=%i", txtMaster.text, [txtMaster.text length]);
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if-statement objective-c

-3
推荐指数
1
解决办法
66
查看次数