小编Uma*_*oor的帖子

我希望通过数据来创建XML,我已经从数据库接收数据DataSet或IList<Booking>.现在我正在使用DataSet此代码创建XML.

string result = String.Empty;

using (StringWriter sw = new StringWriter())
 {
   ds.WriteXml(sw);
   result = sw.ToString();
 }

我的XML就是这种形式.

<Booking> 
    <ID>32</ID> 
    <BookingNumber>12120001</BLNumber> 
    <ReferenceNo>ABCED11212280007</ReferenceNo> 
    <Name>Customer Name1</Name> 
    <Address>Customer Address</Address>
</Booking>

<Booking> 
    <ID>33</ID> 
    <BookingNumber>12120002</BLNumber> 
    <ReferenceNo>ABCED11212280008</ReferenceNo> 
    <Name>Customer Name2</Name> 
    <Address>Customer Address2</Address>
</Booking>



<BookingDetail> 
   <ID>206</ID> 
   <BookingID>32</BookingID> 
   <OrderItem>Item1</OrderItem> 
</BookingDetail>

<BookingDetail> 
   <ID>207</ID> 
   <BookingID>32</BookingID> 
   <OrderItem>Item2</OrderItem> 
</BookingDetail>

<BookingDetail> 
   <ID>208</ID> 
   <BookingID>33</BookingID> 
   <OrderItem>Item1</OrderItem> 
</BookingDetail>

<BookingDetail> 
   <ID>209</ID> 
   <BookingID>33</BookingID> 
   <OrderItem>Item2</OrderItem> 
</BookingDetail>

<BookingDetail> 
   <ID>210</ID> 
   <BookingID>33</BookingID> 
   <OrderItem>Item3</OrderItem> 
</BookingDetail>

但我想要这种形式的XML.

<CompleteBooking>
 <Booking> 
    <ID>32</ID> 
    <BookingNumber>12120001</BLNumber> 
    <ReferenceNo>ABCED11212280007</ReferenceNo> 
    <Name>Customer Name1</Name> 
    <Address>Customer Address</Address>
 </Booking>

 <BookingDetail> 
   <ID>206</ID> …