小编Ale*_*gon的帖子

我有以下显示通知的操作，然后将其删除，我正在尝试为此编写一个单元测试，但似乎无法弄清楚如何模拟setTimeout。

export const addNotification = (text, notificationType = 'success', time = 4000) => {
        return (dispatch, getState) =>{
            let newId = new Date().getTime();
            dispatch({
                type: 'ADD_NOTIFICATION',
                notificationType,
                text,
                id: newId
            });
            setTimeout(()=>{
                dispatch(removeNotification(newId))
            }, time)
        }
    };
    export const removeNotification = (id) => (
    {
        type: 'REMOVE_NOTIFICATION',
        id
    });

遵循redux网站上有关异步测试的教程，我提出了以下测试：

    import * as actions from '../../client/actions/notifyActionCreator'
    import configureMockStore from 'redux-mock-store'
    import thunk from 'redux-thunk'

    const middlewares = [ thunk ];
    const mockStore = configureMockStore(middlewares);


    describe('actions', ()=>{

        it('should create an action …