我正在尝试编写一个简单的过程,它只保留一个输入列表(包括嵌套列表).
程序本身 -
def is_list(p):
return isinstance(p, list)
def deep_reverse(input):
result = []
if len(input) == 0:
return []
for element in input:
if is_list(element) == True:
deep_reverse(element)
else:
appended = input.pop
result.append(appended)
print result
return result
我正在输入什么来执行程序 -
p = [1, [2, 3, [4, [5, 6]]]]
print deep_reverse(p)
print p
结果 -
[built-in method pop of list object at 0xb752b0cc]
[built-in method pop of list object at 0xb7529c6c]
[built-in method pop of list object at 0xb7529cec]
[built-in method pop …我目前正试图解决问题"从1到20的所有数字可以被整除的最小正数是多少？"
到目前为止,我编写了一些似乎有用的内容,但需要很长时间.此外,我需要在if中使用大量的'和'语句,这看起来效率不高也不专业.
我该怎么做才能优化这些代码并使其更整洁？
number = 1
result = 0
def divide(candidate):
if candidate % 2 == 0 and candidate % 3 == 0 and candidate % 4 == 0 and candidate % 5 == 0 and candidate % 6 == 0 and candidate % 7 == 0 and candidate % 8 == 0 and candidate % 9 == 0 and candidate % 10 == 0 and candidate % 11 == 0 and candidate % 12 == 0 and candidate % …我怎么会产生指定长度的星号(所以我可以用它旁边一个数组项的.长度属性)的字符串？
我正试图解决一个问题,但是我觉得我得到的循环在某个地方有一个缺失的链接......
我已经给出了简报 - "现在编写一个程序,计算所需的最低固定月付款,以便在12个月内偿还信用卡余额."
从本质上讲,我所做的远远不是代码,它会取一个基本价值(例如10),从信用卡余额(考虑到利息)中拿走它,如果是它的总月数将余额变为负数(例如已付清)高于12,它会增加'minmonth'(每月还清金额),直到月数等于或低于12.
提前道歉,我实际上只学习了2天的Python!
我哪里错了？
balance = float(raw_input('Enter the outstanding balance on your creditcard: '))
interest = float(raw_input('Enter the annual credit card interest rate as a decimal: '))
minmonth = 10
months = 0
monthlyinterest = interest / 12
while(balance > 0):
balance = balance * (1 + monthlyinterest) - minmonth
months = months + 1
if(months > 12):
months = 0
minmonth = minmonth + 10
else:
print 'RESULT!'
print 'Total amount to pay per month would …