小编use*_*956的帖子

我需要一些帮助,使用音频html标签制作一个非常简单的Jquery播放列表.到目前为止我得到了他的:

<audio id="myAudio" preload="auto">
  Your user agent does not support the HTML5 Audio element.
</audio>

和jquery部分:

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.0/jquery.min.js"></script>
<script>

$(document).ready(function() {
  bgAudio = document.getElementById("myAudio");
  bgAudio.volume = 0.3;

  bgAudio.controls = true;
  bgAudio.loop = true;
  bgAudio.autoplay = true;

  bgAudio.src = "bg1.mp3";
  bgAudio.src = "bg2.mp3";
  bgAudio.play();

});
</script>

我该如何让这两个mp3一个接一个播放？谢谢您的帮助.

我正在生成密码random_int,但我注意到一些奇怪的东西.有时(纯粹随机),它会生成小于最小值的密码.例如,我设置10和15限制,每一次大约50-70尝试它弹出一个2-3字符长密码.我的脚本有问题吗？重现输出很难,只需刷新脚本直到得到类似的结果.

<?php 

    $r_number = random_int( 10 , 15 );

    function random_str(
        $length,
        $keyspace = '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ,./<>?;:"|[]{}-=_+`~!@#$%^&*'
    ) {
        $str = '';
        $max = mb_strlen($keyspace, '8bit') - 1;
        if ($max < 1) {
            throw new Exception('$keyspace must be at least two characters long');
        }
        for ($i = 0; $i < $length; ++$i) {
            $str .= $keyspace[random_int(0, $max)];
        }
        return $str;
    }

    $password = random_str($r_number);

    echo $password;

?>