小编kn3*_*n3l的帖子

我得到了教程

http://www.rmunn.com/sqlalchemy-tutorial/tutorial.html

当我编译得到错误消息

The debugged program raised the exception unhandled NameError
"name 'BoundMetaData' is not defined"

我使用的是最新的sqlAlchemy.

我怎么能修好这个？

阅读本文后,我修改了自己的最新版本sqlAlchemy:

from sqlalchemy import *
engine = create_engine('mysql://root:mypassword@localhost/mysql')
metadata = MetaData()
users = Table('users', metadata,
    Column('user_id', Integer, primary_key=True),
    Column('name', String(40)),
    Column('age', Integer),
    Column('password', String),
)
metadata.create_all(engine) 
i = users.insert()
i.execute(name='Mary', age=30, password='secret')
i.execute({'name': 'John', 'age': 42},
          {'name': 'Susan', 'age': 57},
          {'name': 'Carl', 'age': 33})
s = users.select()
rs = s.execute()
row = rs.fetchone()
print 'Id:', row[0]
print 'Name:', row['name']
print 'Age:', row.age …

我有一个数组,其中包含我想用分页显示的数据.

$display_array = Array
(
    [0] => "0602 xxx2",
    [1] => "0602 xxx3",
    [2] => 5 // Total= 2+3
    [3] => "0602 xxx3",
    [4] => "0602 saa4",
    [5] => 7 // Total = 3+4
)

我尝试过这样的事情

function pagination($display_array, $page)
{   
    global $show_per_page;
    $page = $page < 1 ? 1 : $page;
    $start = ($page - 1) * $show_per_page;
    $end = $page * $show_per_page;
    for($i = $start; $i < $end; $i++)
    {
        ////echo $display_array[$i] . "<p>";
        // How to manipulate this? …

Python 3.2 (r32:88445, Feb 20 2011, 21:29:02) [MSC v.1500 32 bit (Intel)] on win32
Type "copyright", "credits" or "license()" for more information.
>>> str_version = '??????'
>>> type(str_version)
<class 'str'>
>>> print (str_version)
??????
>>> unicode_version = '??????'.decode('utf-8')
Traceback (most recent call last):
  File "<pyshell#3>", line 1, in <module>
    unicode_version = '??????'.decode('utf-8')
AttributeError: 'str' object has no attribute 'decode'
>>> 

我的unicode字符串有什么问题？

例如,我通过将字典作为参数传递来调用此函数:

>>> inv_map({'a':1, 'b':2, 'c':3, 'd':2})
{1: ['a'], 2: ['b', 'd'], 3: ['c']}
>>> inv_map({'a':3, 'b':3, 'c':3})
{3: ['a', 'c', 'b']}
>>> inv_map({'a':2, 'b':1, 'c':2, 'd':1})
{1: ['b', 'd'], 2: ['a', 'c']}

如果

map = { 'a': 1, 'b':2 }

我只能将此地图反转为:

inv_map = { 1: 'a', 2: 'b' }

通过使用这个

dict((v,k) for k, v in map.iteritems())

任何人都知道如何为我的情况这样做？

我有6个表,我将做一个单独的SQL语句:

1)participant
  ***********
  +id_participant
  +id_poste
  +name
  +email

2) profile_formaion
  ****************
  +id_poste
  +id_formation

3) formation
  *********
  +id_formation
  +lable

4) poste
  *********
  +id_poste
  +label

5) session
  *********
  +id_session
  +id_formaion
  +lable

6) session_composition
  *********
  +id_session
  +id_participant

EXAMPLE:

数据:参与者

1 | 2 | user1 | user1@mail.com
2 | 3 | user2 | user2@mail.com

数据:profile_formation

2 | 3
2 | 4

DATA:形成

1 |formation1
2 |formation2
3 |formation3
4 |formation4

数据:poste

1 |Poste1
2 |Poste2
3 |Poste3

DATA:会话

1 |1   /* id_session 1 to id_formation …

我正在尝试使用我的Play-2.5项目配置Swagger.

我按照本教程进行了操作,但仅适用于较旧版本的Play而不使用Play-2.5.随着项目迁移到Play-2.5,我们不得不删除swagger配置.

首先,问题似乎是Play-2.5中的静态控制器与非静态控制器,但我最终证明自己是错的.我正面临这个错误

      type ApiHelpController is not a member of package controllers 
      GET         /api-docs                controllers.ApiHelpController.getResources

如果任何人知道Play-2.5 for Java的 Swagger配置链接,请指导.

PS:有Scala的教程不适用于java.

在我的views.py中,我有一个方法:

#......
def get_filter_result(self, customer_type, tag_selected):
        list_customer_filter=[]
        customers_filter = Customer.objects.filter(Q(type__name=customer_type),
                                                   Q(active=True),
                                                   Q(tag__id=tag_selected))

        for customer_filter in customers_filter:
                    customer_filter.list_authorize_sale_type = sale_type_selected(customer_filter.authorize_sale_type)
                    list_customer_filter.append(customer_filter)
        return list_customer_filter

**我的案例tag_selected是用户选中的复选框值我遇到了tag_selected(是列表= 1,2,3,...)从我的网址传递的问题

/?customer_type=TDO&tag=2 ===>filter okay
/?customer_type=TDO&tag=3 ===>filter okay
?customer_type=TDO&tag=2,3 ===>How Can I add And condition in filter?

例如

if len(tag_selected)==1:
      customers_filter = Customer.objects.filter(Q(type__name=customer_type),
                                                       Q(active=True),
                                                       Q(tag__id=tag_selected))
else:
    customers_filter = Customer.objects.filter(Q(type__name=customer_type),
                                                       Q(active=True),
                                                       Q(tag__id=tag_selected[0])
                                                       Q(tag__id=tag_selected[1])
                                                       Q(tag__id=tag_selected[2])
                                                       ...
                                                        )

以下代码适合我:

# -*- coding: utf-8 -*-
N = int(raw_input("N="))
l=[]
i = 0
while i<N:
   n = raw_input("e"+str(i)+"=")
   l.append(n) 
   i = i+1   
print l  

但是,为什么我不能通过使用l[i] = raw_input("e"+str(i)+"=")来简化它呢？

示例:(不起作用)

# -*- coding: utf-8 -*-
N = int(raw_input("N="))
l=[]
i = 0
while i<N:
   l[i] = raw_input("e"+str(i)+"=")
   i = i+1   
print l 

我想限制用户输入,以便提供Nobeys N >0或N < 100.

我应该使用if... else或try... except？你能提供两种方法的例子吗？

我想要 Union 2 数组$A和$B示例：

$A = Array(
    0=>array(
            'lable' =>"label0",
            'id_poste'=>1,
            'id_part'=>11
    ),
    1=>array(
            'lable' =>"label1",
            'id_poste'=>2,
            'id_part'=>12
            ),
    2=>array(
            'lable' =>"label2",
            'id_poste'=>3,
            'id_part'=>13
    ),
    3=>array(
            'lable' =>"label3",
            'id_poste'=>4,
            'id_part'=>14
            )
);

$B = Array(
    0=>array(
            'lable' =>"label0",
            'id_poste'=>1,
            'id_part'=>11
    ),
    1=>array(
            'lable' =>"label1_X",
            'id_poste'=>2,
            'id_part'=>12
            ),
    2=>array(
            'lable' =>"label2",
            'id_poste'=>3,
            'id_part'=>13
    ),
    3=>array(
            'lable' =>"label3_X",
            'id_poste'=>4,
            'id_part'=>14
            )
);

这两个数组之间的并集结果将是

/*
$result => Array(
    0=>array(
            'lable' =>"label0",
            'id_poste'=>1,
            'id_part'=>11
    ),
    1=>array(
            'lable' =>"label1",
            'id_poste'=>2,
            'id_part'=>12 …