小编T_T*_*T_T的帖子

我使用Metadata和JsonIgnore来删除序列化中的特殊字段.

[Authorize(Roles = "admin")]
public class UserController : ApiController
{
    public IEnumerable<user> Get()
    {
        using (var mydb = new ModelContainer())
        {
            return mydb.userSet.ToList();
        }
    }
}

[MetadataType(typeof(user_Metadata))]  
public partial class user
{  
    private class user_Metadata  
    {  
        [JsonIgnore]  
        public virtual password { get; set; }  

        public virtual adminFile { get; set; }  
    }  
}  

如何动态控制应该序列化哪个字段.对于某些事情

public partial class user
{  
    private class user_Metadata  
    {  
        [JsonIgnore]  
        public virtual password { get; set; }  
        [Roes == admin?JsonIgnore:JsonNotIgnore] //some thing like this
        public virtual …

我可以轻松地在C#中获得异步设计

HttpResponseMessage response = await httpClient.GetAsync(InputAddress.Text);
{
    ....// run when request finished. And response closely relation to request.
}

但是我怎么能在QT中做到这一点？我在下面找到一些代码.但还是有些问题.

1. 为什么(sentReply == reply)可以确定它是否相同？也许我可以发送两次相同的请求,请求A,请求B.相应的响应是A',B'.但响应按照B',A'顺序到达.代码工作与否？

2. 如果我想在请求完成时运行一些代码(如上面的c#代码),我该怎么做？我想我可以将UUID绑定到每个请求或绑定一个回调函数指针来请求？最好的方法是什么？

   QNetworkAccessManager *manager=new QNetworkAccessManager(this);
   connect(manager,SIGNAL(finished(QNetworkReply*)),this,SLOT(requestFinished(QNetworkReply*)));
   QNetworkRequest request(QUrl(serverUrl));
   QNetworkReply *sentReply = manager->post(request, buffer.toUtf8());
   
   void requestFinished(QNetworkReply *reply)
   {
       QByteArray msg = reply->readAll();
       if (sentReply == reply)
       qDebug("this is it");
   }
   

   Run Code Online (Sandbox Code Playgroud)

根据qlogging.h

#define qDebug QMessageLogger(__FILE__, __LINE__, Q_FUNC_INFO).debug

但是当我使用这样的时候,文件,行,功能名称都没有显示出来.

qDebug()<< "abc"; // only show abc;
qDebug()<< "";    // show nothing;

我搜索了一会儿,似乎没有人像我上面那样有问题.

我使用ubuntu14.04,g ++版本4.8.2,从git构建qt5.3.

这是我的HttpService类,它工作正常.但它看起来很奇怪,每个函数中的代码都大致相同.我应该在每个函数中编写try/catch,特别是TaskCanceledException,如果我没有在这里捕获它,我的应用程序将终止.有人能给我一些关于如何优化代码的例子吗？

[Export(typeof(IDataSource))]
public class HttpService : IDataSource
{
    HttpClient client = new HttpClient();
    public HttpService()
    {
        client.BaseAddress = new Uri("https://localhost:3721");
        client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));
    }

    public void Initialize(CurrentUser currentUser)
    {
        client.DefaultRequestHeaders.Authorization = new AuthenticationHeaderValue("Basic",
            Convert.ToBase64String(Encoding.UTF8.GetBytes(currentUser.Name + ":" + currentUser.Password)));
    }

    public async Task<IEnumerable<User>> getUsers()
    {
        try
        {
            var response = await client.GetAsync("api/User");
            //response.EnsureSuccessStatusCode(); // Throw on error code.
            if (response.IsSuccessStatusCode)
            {
                var result = await response.Content.ReadAsAsync<IEnumerable<User>>();
                return result;
            }
            else
            {
                return null;
            }
        }
        catch (Newtonsoft.Json.JsonException ex)
        {
            Console.WriteLine(ex.ToString());
        }
        catch …

应用程序的窗口没有边框,所以右边没有退出按钮？如何以正确的方式关闭它？

这是我的方式,fisrt将命令绑定到自定义退出按钮.

<Button Content="Exit" HorizontalAlignment="Left" Margin="327,198,0,0" VerticalAlignment="Top" Width="75" Command="{Binding ExitCommand}"/>

单击按钮时在ViewModel中抛出异常.

class ViewModel:NotificationObject
{
    public ViewModel()
    {
        this.ExitCommand = new DelegateCommand(new Action(this.ExecuteExitCommand));
    }

    public DelegateCommand ExitCommand { get; set; }

    public void ExecuteExitCommand()
    {
        throw new ApplicationException("shutdown");
    }
}

在Application类中捕获异常

public partial class App : Application
{
    protected override void OnStartup(StartupEventArgs e)
    {
        base.OnStartup(e);
        Bootstrapper bootstrapper = new Bootstrapper();
        AppDomain.CurrentDomain.UnhandledException += AppDomainUnhandledException;
        try
        {
            bootstrapper.Run();
        }
        catch (Exception ex)
        {
            HandleException(ex);
        }
    }

    private static void AppDomainUnhandledException(object sender, UnhandledExceptionEventArgs e) …