小编Sar*_*ang的帖子

Symfony 3.0安装

是symfony的新手,从上个月开始,我在终端上使用ubuntu上的以下命令不断安装新的symfony项目

# Linux, Mac OS X
$ symfony new my_project_name
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它一直工作到今天,但不仅检查了新版本,但现在它开始给我跟随错误

Downloading Symfony...

    4.93 MB/4.93 MB ????????????????????????????????????????????????????????????  100%

 Preparing project...

PHP Warning:  require(/var/www/projectname/app/SymfonyRequirements.php): failed to open stream: No such file or directory in phar:///usr/local/bin/symfony/src/Symfony/Installer/DownloadCommand.php on line 265
PHP Stack trace:
PHP   1. {main}() /usr/local/bin/symfony:0
PHP   2. require() /usr/local/bin/symfony:10
PHP   3. Symfony\Component\Console\Application->run() phar:///usr/local/bin/symfony/symfony:35
PHP   4. Symfony\Component\Console\Application->doRun() phar:///usr/local/bin/symfony/vendor/symfony/console/Application.php:126
PHP   5. Symfony\Component\Console\Application->doRunCommand() phar:///usr/local/bin/symfony/vendor/symfony/console/Application.php:195
PHP   6. Symfony\Component\Console\Command\Command->run() phar:///usr/local/bin/symfony/vendor/symfony/console/Application.php:878
PHP   7. Symfony\Installer\NewCommand->execute() phar:///usr/local/bin/symfony/vendor/symfony/console/Command/Command.php:259
PHP   8. Symfony\Installer\DownloadCommand->checkSymfonyRequirements() phar:///usr/local/bin/symfony/src/Symfony/Installer/NewCommand.php:65
PHP Fatal error:  require(): Failed opening required '/var/www/projectname/app/SymfonyRequirements.php' …
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php symfony

18
推荐指数
1
解决办法
2528
查看次数

如何在bash脚本中迭代json

我有如下的json,我需要在bash脚本中只获取上面json的邮件

value = {"count":5,"users":[{"username":"asa","name":"asa Tran","mail":"asa@xyz.com"},{"username": "qq","name":"qq Morris","mail":"qq@xyz.com"},{"username":"qwe","name":"qwe Org","mail":"qwe @ xyz.com"}]}

输出可以是

mail=asa@xyz.com,qq@xyz.com,qwe@xyz.com
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以上所有内容都需要在bash脚本(.sh)中完成

我已经尝试过使用数组迭代但没有用

for key in "${!value[@]}"
do
        #echo "key = $key"
        echo "value = ${value[$key]}"
done
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即使我已尝试使用数组转换

alias json-decode ="php -r'print_r(json_decode(file_get_contents(\"php:// stdin \"),1));'"value = $(curl --user $ credentials -k $ endPoint | json-解码)

仍然我无法获得具体的输出.

bash json

6
推荐指数
2
解决办法
1万
查看次数

无法解析包含unicode十六进制字符的JSON字符串

var mystring = '{"Customers":[{"CustomerCity":"Zaragoza","CustomerFName":"Ana","CustomerAddress":"C/ El Temple, 9 2\\xbaB","CustomerCountry":"es"}]}';

var myparsestring = JSON.parse(mystring);
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错误:

JSON中出现意外的标记x

javascript jquery json

1
推荐指数
1
解决办法
943
查看次数

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