小编ess*_*eev的帖子

考虑这个简单的枚举类:

#include <QObject>
class BookTypes : public QObject
{
    Q_GADGET
    Q_ENUMS(AllBooksType)    

public:

    enum AllBooksType{
        eMagazine,
        eReference,
        eTextBook,
        eThesis
    };

signals:

public slots:

};

输入注册 main()

qmlRegisterUncreatableType<BookTypes>("trial", 1, 0, "BookTypes", 
"Don't create qml instance for BookTypes");

这是QML示例:

Rectangle {
        id: rect
        x: 100; y: 100
        width: 100
        height: 70
        color: "PowderBlue"
        border.color: "RoyalBlue"
        border.width: 1
        radius: 3

        MouseArea{
            x: 0; y: 0
            height: parent.height
            width: parent.width
            property int bt: BookTypes.eTextBook //perfect. now bt is 2
            onClicked: {
                console.debug("old book type:- ") …

我有一个集合定义为 -

using Parameters = std::vector<int>;
using Group = std::pair<std::string, Parameters>;
std::vector<Group> inputs;

我的意图是使用像这样的陈述

inputs.push_back(group0 /*What goes in here ?*/);
inputs.push_back(group1 /*What goes in here ?*/);

如何初始化group0和group1使用初始化列表？像这样的代码似乎不起作用

inputs.push_back(std::make_pair("group0", {1, 2, 3, 4}));

编辑:有是矢量,对初始化已经存在的问题,但我看不出任何地方second的std::pair又是一个集合.

在假设的例子中,我有一个C++组件 -

class Board : public QObject
{
    Q_OBJECT
public:
    //Q_PROPERTYs go here
    explicit Board(int rows, int columns)
    {
        matrix = std::vector<int>(rows, std::vector<int>(columns, 0));
    }

    ~Board()
    {
        matrix.clear();
    }

    Q_INVOKABLE void checkAndUpdateAdjecentCells(int row, int column);
    //setters and getters here.

signals:
    void matrixUpdated();

private:
    Board(QObject *parent) = default; //i intend to do this.
    Board(Board& b) = delete;
    int nRows_, nCols_;
    std::vector<std::vector> matrix;
};

注册于main()像-

qmlRegisterType<Board>("SameGameBackend", 1, 0, "BubbleBoard");

题

如何在QML中实例化这样,以便调用参数化构造函数？

预期的QML代码 -

BubbleBoard{
    id: bboard
    rows: 10
    columns: 10 …