小编Man*_*lai的帖子

我有数据如下：

ID  Gender  Country  ...
1   Male    UK
2   Female  US
3   Male    NZ
4   Female  UK
...

性别只有 2 个选项，国家只有 3 个选项。我想为“性别”和“国家”创建一个单独的饼图，以显示每个选项在数据中出现的次数，但我对如何做到这一点感到非常困惑。

数据存储在 pandas 数据框中。

非常感谢任何和所有的帮助！

目前我正在使用以下代码进行替换，这有点麻烦：

df1['CompanyA'] = df1['CompanyA'].str.replace('.','')
df1['CompanyA'] = df1['CompanyA'].str.replace('-','')
df1['CompanyA'] = df1['CompanyA'].str.replace(',','')
df1['CompanyA'] = df1['CompanyA'].str.replace('ltd','limited')
df1['CompanyA'] = df1['CompanyA'].str.replace('&','and')
df1['Address1A'] = df1['Address1A'].str.replace('.','')
df1['Address1A'] = df1['Address1A'].str.replace('-','')
df1['Address1A'] = df1['Address1A'].str.replace('&','and')
df1['Address1A'].str.replace(r'\brd\b', 'road')
df1['Address2A'] = df1['Address2A'].str.replace('.','')
df1['Address2A'] = df1['Address2A'].str.replace('-','')
df1['Address2A'] = df1['Address2A'].str.replace('&','and')
df1['Address2A'].str.replace(r'\brd\b', 'road')

为了使即时更改更容易，我的理想情况是这样的：

df1['CompanyA'] = df1['CompanyA'].str.replace(('&','and'), ('.', ''), ('-','')....)
df1['Address1A'] = df1['Address1A'].str.replace(('&','and'), ('.', ''), ('-','')....)
df1['Address2A'] = df1['Address2A'].str.replace(('&','and'), ('.', ''), ('-','')....)

这样我就可以输入/更改我想为特定列替换的内容，而无需调整多行代码。

这可能吗？