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Python 子字符串 - 将第 n 个字符拆分到某个字符串的左侧

我有以下示例字符串:

0015CB,0,0,01,006D,0016CF1,4,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00F4E7D,1,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,0008184,8,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00FA704,9,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,0014EC8,2,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00FAEEA,9,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00FADE9,5,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00FA5A5,3,000D
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请您告诉我如何在每次迭代的左侧获得 9 个字符"000D",因此第一个结果将是:

0016CF1,4
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第二次提取将是:

00F4E7D,1
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第三个是:

0008184,8
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等等。我已经尝试过 split 函数并且正在努力掌握正则表达式。

python split substring python-3.x

3
推荐指数
1
解决办法
65
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python ×1

python-3.x ×1

split ×1

substring ×1