小编leo*_*ina的帖子

我已经为主题自定义创建了一个函数.

function create_theme_option() {

        add_menu_page(  'Manage Options', //Page Title 

                        'Theme Option', //WP Administrator Menu Title

                        'manage_options', //

                        'theme-options', //Link to a page to your Administration Area

                        'deploy_theme_options', //Function Name

                        get_template_directory_uri() . '/Plugins/Background Changer/images/icons/icon.png',//Menu Icon 

                        99);

        add_submenu_page("theme-options", "Theme Settings", "Theme Settings", 1, "theme-settings", "theme_settings");

        add_submenu_page("theme-options", "Manage Header", "Manage Header", 1, "manage-header", "manage_header");

        add_submenu_page("theme-options", "Social Media", "Social Media Links", 1, "social-media", "social_media");

        add_submenu_page("theme-options", "Catalog Manager", "Catalog Manager", 1, "catalog-manager", "catalog_manager");

    }

但我注意到在标题"主题选项"之后,旁边会出现另一个文本作为"主题选项".检查下面的图片:

我怎样才能解决这个问题？请帮忙!

我是PHP的新手,我对使用IN参数的select语句有一些疑问.

<?php

$resultID = "333\n334\n335\n0";

$reconResult = str_replace("\n",",",$resultID);

//$reconResult will display 333,334,335,0

$query = mysql_query('SELECT * FROM tbl_name WHERE tbl_item_id IN($reconResult)');

if(mysql_num_rows($query)>0){
     while($r=mysql_fetch_object($query)){
         echo $r->tbl_item_name;
     }
}

?>

我只想显示包含来自$ reconResult的id的项目;

提前致谢.