小编Jon*_*nts的帖子

我是OS X 10.8上运行2.7.6的Python初学者,添加了numpy和pyobjc.这是我正在尝试运行的脚本:

from __future__ import with_statement
from Foundation import NSMutableDictionary, NSUserDefaults, NSCFArray, objc
import numpy as np
from copy import copy
import os
import re

domainName = "org.mworks-project.MWClient"

outFile = os.path.expanduser(os.path.join('~/Desktop','org.Behavior.MWClientSavedVars.plist'))
keyNames = [ 
  'MATLAB client window - selected variables',
  'MATLAB client window - MATLAB .m file',
  'recentPythonScripts' ]

homedir = os.getenv('HOME')

################

def subStr(inStr):
    return re.sub('^%s'%homedir, '$HOME', inStr)

def replaceUserdirWithStr(inObj):
    if type(inObj) == str or type(inObj) == objc.pyobjc_unicode:
        return subStr(inObj)
    elif isinstance(inObj, NSCFArray):
        for i in range(len(inObj)):
            # …

我正在学习python文件处理.我尝试使用此代码一次读取一个字符

f = open('test.dat', 'r')

while (ch=f.read(1)):
    print ch

为什么它不起作用

这是错误消息

C:\Python27\python.exe "C:/Users/X/PycharmProjects/Learning Python/01.py"
File "C:/Users/X/PycharmProjects/Learning Python/01.py", line 4
while (ch=f.read(1)):
         ^
SyntaxError: invalid syntax

Process finished with exit code 1

我是 Python 新手，并且一直坚持打印由分隔符分隔的数组元素。我的数组由 60 000 奇数行组成，每行 26 个元素，其中一些元素仅包含数字，而其他元素则包含各种字符，包括特殊字符。例子：

a[0] = [abc,123,a1b2c3,*wewqe,...] 
a[1] = [098i,qwerty,123qwe,xx-u,...]

我希望输出是（最后一个元素后面没有“|”并且每一行都在自己的行上：

abc|123|a1b2c3|*wewqe,...
098i|qwerty|123qwe|xx-u,...

我已尝试以下方法，但它们不起作用：

for row in results :
    length = len(row)
    print("")#throw in a new line
    print ("Number of elements: " + str(length))
    print '|'.join((str(row)))

和这个：

for row in results :
    length = len(row)
    print("")#throw in a new line
    print ("Number of elements: " + str(length))
    for item in row:
            print '|'.join(str(item))

和这个：

 for row in results :
    length = len(row)
    print("")#throw in a new …

当我使用运行时检查编译程序时，出现以下错误（我不知道为什么）：

ifort -check all test.f90 -o test
./test
forrtl: severe (193): Run-Time Check Failure. The variable 'my_sum$2$_2' is being used without being defined
Image        PC                     Routine           Line           Source
sum          0000000000403098       Unknown              Unknown     Unknown 
sum          0000000000403098       Unknown              Unknown     Unknown 
sum          0000000000403098       Unknown              Unknown     Unknown 
sum          0000000000403098       Unknown              Unknown     Unknown 
.
.
.
sum          0000000000403098       Unknown              Unknown     Unknown 
sum          0000000000402EAF       Unknown              Unknown     Unknown 
sum          0000000000402DE6       Unknown              Unknown     Unknown 
libc.so.6    00007F7FEB268BE5       Unknown              Unknown     Unknown 
sum          0000000000402CD9       Unknown              Unknown     Unknown 

代码是：

program test

   implicit …

我的意见是

email_list = 

"mail1@mail.com,mail2@mail.com, mail3@mail.com mail4@mail.com 
mail5@mail.com"

例外输出是

['mail1@mail.com', 'mail2@mail.com', 'mail3@mail.com', 'mail4@mail.com', 'mail5@mail.com']

我试过这个方法,但它只会拆分(,)分开.请告诉我.

output = email_list.split(',') 

提前致谢...

我使用此代码来编码和压缩文本。但是它不能正常工作：

Traceback (most recent call last): File "E:\SOUND.py", line 114, in <module>
unhexsring = str(zlib.decompress(unhexsring).encode('utf8'))
TypeError: a bytes-like object is required, not 'str' 

你能帮助我吗？

import zlib,gzip

def str2hex(s):
    return binascii.hexlify(bytes(str.encode(s)))


def hex2str(h):
    return binascii.unhexlify(h)

hexstring = input()
if len(hexstring) > 200:
    hexstring = str(zlib.compress(hexstring.encode('utf-8')))
    print(hexstring)
hexstring = str2hex(hexstring)
ph = str(hexstring.decode('utf-8'))
print(ph)

#decompressing text
unhexsring = hex2str(hexstring).decode('utf8')
if 'x' in str(unhexsring):
    print('compressed')
    unhexsring = str(zlib.decompress(unhexsring).encode('utf8'))
print(unhexsring)

此代码不会解压缩zlib压缩的文本。

因此编码工作良好。

我的麻烦是当我获取编码的字符串并对其进行压缩时，我无法对其进行解压缩。应该如何运作：

1>s = input('some text')
2>if len(s) > 200: s = str(zlib.compress(s.encode('utf-8'))) …

所以我有一个try/except块设置,它将根据某些条件通过数据库:

try:
    for searchnumber in itertools.count(0):
        print searchnumber
        c.execute("""SELECT words from searchterms where onstate = 1 AND progid = %d;""") % searchnumber
        searchterms = (c.fetchall())
        searchterms = [",".join(x) for x in searchterms]
        print searchterms
except:
    pass

由于某种原因,它不是在progid上迭代,事实上,它甚至没有为它分配第一个值(0).为什么会这样？据我所知,%d应该用searchnumber的整数值代替

用字符'^'替换字符串中的所有单词字符后,使用re.sub("\w", "^" , stringorphrase)我留下:

>>> '^^^ ^^ ^^^^'

有没有办法删除单引号,使它看起来更干净？

>>> ^^^ ^^ ^^^^

使用IMAPClient如何查看邮件正文和发件人电子邮件地址？

server = IMAPClient(imap_server, use_uid=True, ssl=ssl)
server.login(imap_user, imap_password)

print 'login successful'

select_info = server.select_folder('INBOX')
print '%d messages in INBOX' % select_info['EXISTS']

messages = server.search(['NOT DELETED'])
print "%d messages that aren't deleted" % len(messages)

print
print "Messages:"
response = server.fetch(messages, ['FLAGS', 'RFC822.SIZE'])
for msgid, data in response.iteritems():
    print '   ID %d: %d bytes, flags=%s' % (msgid,
                                            data['RFC822.SIZE'],
                                            data['FLAGS'])

我在理解类中的继承方面遇到了一些麻烦,并想知道为什么这些python代码不起作用,有没有人可以告诉我这里出了什么问题？

## Animal is-a object 
class Animal(object):
    def __init__(self, name, sound):
        self.implimented = False
        self.name = name
        self.sound = sound

    def speak(self):
        if self.implimented == True:
            print "Sound: ", self.sound

    def animal_name(self):
        if self.implimented == True:
            print "Name: ", self.name



## Dog is-a Animal
class Dog(Animal):

    def __init__(self):
        self.implimented = True
        name = "Dog"
        sound = "Woof"

mark = Dog(Animal)

mark.animal_name()
mark.speak()

这是通过终端的输出

Traceback (most recent call last):
  File "/private/var/folders/nd/4r8kqczj19j1yk8n59f1pmp80000gn/T/Cleanup At Startup/ex41-376235301.968.py", line 26, in <module>
    mark = Dog(Animal)
TypeError: …