小编cba*_*wat的帖子

我有一本字典列表的字典.如下所示:

x = {'a':[{'p':1, 'q':2}, {'p':4, 'q':5}], 'b':[{'p':6, 'q':1}, {'p':10, 'q':12}]}

列表(值)的长度对于dict x的所有键都是相同的.我想得到任何一个值的长度,即列表而不必通过明显的方法 - >获取密钥,使用len(x [keys [0]])来获取长度.

我现在的代码:

val = None
for key in x.keys():
    val = x[key]
    break
    #break after the first iteration as the length of the lists is the same for any key
try:
    what_i_Want = len(val)
except TypeError:
    print 'val wasn't set'

我对此并不满意,我相信可以做得更加"pythonic".