小编did*_*ido的帖子

下面的陈述是否正确如下."一个男人有一个最好的朋友是狗."

public class Mann {
     private BestFriend dog;
     //etc
}

考虑到下面的代码,如果catch子句中抛出异常,最终是否仍会运行？

try {
//code here throws exception
}
catch(Exception ex) {
//code catches above exception however code here also throws another exception
}
finally {
//does this code even run considering the exception thrown in the above catch clause??
}

可能重复:
在插入之前检查重复的Insert语句

我想使用外键b_id检查问题日志表中是否存在构建ID.如果它不存在,那么我想将其添加到问题日志表中.我有下面的代码,但这只是检查问题日志表中哪些建筑物不在...我怎么能插入？非常感谢.我正在使用SQL Server 2008.

select b.b_id from building 
where not exists(select b.b_id from issue_log as l where b._id = l.b_id)

我在一台网络上,我的机器是10.0.0.81,子网掩码是255.255.255.0.我想找出我的广播地址.那会是10.0.0.255吗？如果是这样,我该如何验证？我可以发送一个ping例子,看看它击中了哪台电脑？

我有以下代码总是导致0.00.我确定weight_score是一个实际数字.有人可以帮我格式化它,以便产生十进制数.使用SQL Server 2008,此代码位于视图中.非常感谢!

CAST(SUM(weight_score * (45/100)) as decimal(10,2)) As avg_score

我有下面的查询,我正在寻找优化它的方法(等使它更有效和更快).有没有人有任何想法？

SELECT s.oem_id, s.name, SUM(u.minimum_gfs) AS minimum_gfs, sum(u.minimum_ofs) AS    
   minimum_ofs, sum(u.minimum_wq) AS minimum_wq
FROM nmp_building_reqs AS s
   LEFT OUTER JOIN nmp_building_util AS u
ON u.oem_id = s.oem_id
GROUP BY s.oem_id, s.name

I have the following regex expression (code below), however I am very confused as to why it does not return 'Banas' since it is a word and is between 2 and 20 characters.

    Pattern p = Pattern.compile("\\s[A-Za-z]{2,20}\\s");
    Matcher m = p.matcher(" Derek Banas CA 1234 PA (750)555-1234");

    while(m.find()){
    System.out.println(m.group());
    }

The output is below. Why is "Banas" not in the output? Thanks.

Derek CA PA