小编Uch*_*ara的帖子

嗨,我正在尝试创建一个动态创建一个委托的函数,该委托具有相同的返回值和与它作为参数接收的MethodInfo相同的参数,这也是相同的参数名称非常重要!

到目前为止我所做的是创建一个函数,该函数返回一个lambda,它接收相同的参数类型,并且具有与MethodInfo相同的返回值,但它没有参数名称:

    static void Example()
    {
        Person adam = new Person();
        MethodInfo method = typeof(Person).GetMethod("Jump");
        Delegate result = CreateDelegate(adam, method);
        result.DynamicInvoke((uint)4, "Yeahaa");
    }

    private static Delegate CreateDelegate(object instance, MethodInfo method)
    {
        var parametersInfo = method.GetParameters();
        Expression[] expArgs = new Expression[parametersInfo.Length];
        List<ParameterExpression> lstParamExpressions = new List<ParameterExpression>();
        for (int i = 0; i < expArgs.Length; i++)
        {
            expArgs[i] = Expression.Parameter(parametersInfo[i].ParameterType, parametersInfo[i].Name);
            lstParamExpressions.Add((ParameterExpression)expArgs[i]);
        }

        MethodCallExpression callExpression = Expression.Call(Expression.Constant(instance), method, expArgs);
        LambdaExpression lambdaExpression = Expression.Lambda(callExpression, lstParamExpressions);

        return lambdaExpression.Compile();
    }

    private class Person
    {
        public …