我正在尝试在Windows 7上安装tomcat-7.0.27.然后我点击了bin/startup.bat,出现了一个窗口,我在最后一行看到"INFO:761 ms内的服务器启动".然后我尝试检查"http"// localhost:8080"但是下面的信息显示:
HTTP Status 500 -
type Exception report
message
description The server encountered an internal error () that prevented it from fulfilling this request.
exception
org.apache.jasper.JasperException: java.lang.IllegalStateException: No output folder
org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:585)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:391)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)
javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
root cause
java.lang.IllegalStateException: No output folder
org.apache.jasper.JspCompilationContext.createOutputDir(JspCompilationContext.java:738)
org.apache.jasper.JspCompilationContext.getOutputDir(JspCompilationContext.java:196)
org.apache.jasper.JspCompilationContext.getClassFileName(JspCompilationContext.java:581)
org.apache.jasper.compiler.Compiler.isOutDated(Compiler.java:461)
org.apache.jasper.compiler.Compiler.isOutDated(Compiler.java:425)
org.apache.jasper.JspCompilationContext.compile(JspCompilationContext.java:639)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:357)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)
javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
note The full stack trace of the root cause is available in the Apache Tomcat/7.0.27 logs.
Apache Tomcat/7.0.27
然后我在窗口的每个开头都找到了这些信息:
java.util.logging.ErrorManager: 4
java.io.FileNotFoundException: C:\Program Files\apache-tomcat-7.0.27\logs\catalina.2012-05-14.log (Access is …我知道'+','？' 和'*'.但是,如果我想要一些东西重复,比如5次呢？例如,如果标识符必须是长度为5的十六进制数字的字符串？
更具体地说,我正在考虑定义一个无限长度的一般词法分析器规则,然后,在解析时计算它重复的时间,如果等于5,则将其重命名为另一种类型的令牌,但怎么能我这样做？还是有一些简单的方法？