小编Tho*_*eia的帖子

如何渲染.obj文件(在3d中)？我该如何为它添加颜色？我在OS X上,并使用XCode 4.这是我的小'测试实验室'.

#include <GLUT/glut.h>
#include <iostream>

void render(void);

void keyboard(unsigned char c, int x, int y);

void mouse(int button, int state, int x, int y);

int main(int argc, char ** argv) {
    glutInit(&argc, argv);
    glutInitDisplayMode(GLUT_DEPTH | GLUT_DOUBLE | GLUT_RGBA);
    glutInitWindowPosition(100, 100);
    glutInitWindowSize(500, 500);
    glutCreateWindow("Simple GLUT Application");

    glutDisplayFunc(render);
    glutKeyboardFunc(keyboard);
    glutMouseFunc(mouse);

    glutMainLoop();
}

void keyboard(unsigned char c, int x, int y) {
    if (c == 27){
        exit(0);
    }
}

void mouse(int button, int state, int x, int y) {
    if (button …

我有一个快速的效率问题.

假设我有一个经常被设置为YES的布尔值(当玩家在地面时).

检查BOOL的值是否更有效率,即

if (!character.isOnGround) character.isOnGround = YES;

或者将值设置为YES会更高效,即

character.isOnGround = YES

基本上,问题是这个.if语句比赋值更快吗？

我有这个代码:

public void onPlayerInteract(PlayerInteractEvent event) {
    final Action action = event.getAction();
    if (action == Action.LEFT_CLICK_BLOCK){
        Location l1 = event.getClickedBlock().getLocation();
    } else if (action == Action.RIGHT_CLICK_BLOCK) {
        Location l2 = event.getClickedBlock().getLocation();
    }

    Thread t = new Thread() {
        @Override
        public void run() {
            while(true) {
                try {
                    Thread.sleep(1000*60*60);
                    //Insert code here
                } catch (InterruptedException ie) {
                }
            }
        }
    };
    t.start();

如何访问l1的//insert code here？

我有这个代码:

public void onPlayerInteract(PlayerInteractEvent event) {
    final Action action = event.getAction();
    Location l1 = null;
    Location l2 = null;
    if (action == Action.LEFT_CLICK_BLOCK){
        l1 = event.getClickedBlock().getLocation();
    } else if (action == Action.RIGHT_CLICK_BLOCK) {
        l2 = event.getClickedBlock().getLocation();
    }

    Thread t = new Thread() {
        @Override
        public void run() {
            while(true) {
                try {
                    Thread.sleep(1000*60*60);
                    Location maxx = l1.getX();
                    Location maxy = l1.getY();
                    Location maxz = l1.getZ();

                    Location minx = l2.getX();
                    Location miny = l2.getY();
                    Location minz = l2.getZ();

                    if(l1.getX() > l2.getX()){ …

我正在制作一种语言,每当一个人想要访问变量时,它都带有$符号.但是,在每个函数上我必须有一个if,看看它的第一个字母是否为$,并且每次传递参数时,对于每个参数我都必须这样做.它变得混乱.我想不嵌套if,但有它所以我可以轻松地应用一个函数,并访问它.这有点难以解释,但我会用一些代码来解释.

def varcmd(cmd, variables):
    if cmd.__len__() < 4:
        print "Too little arguments! str <var> = <string>"
    else:
        if cmd[2] == "=":
            if cmd[3][:1] == "$":
                variables[cmd[1]] = variables[cmd[3][1:]]
            else:
                variables[cmd[1]] = cmd[3]
        else:
            print "Incorrect syntax! str <var> = <string>"

当我不断添加到这个函数时,if会以指数方式增加,实际上每个函数都可以获取变量,因此每个函数都会有大量的if.基本上,我想要这样的东西:

def varcmd(cmd, variables):
    if cmd.__len__() < 4:
        print "Too little arguments! str <var> = <string>"
    else:
        if cmd[2] == "=":
            variables[cmd[1]] = auto_convert_if_var.cmd[3][1:]
        else:
            print "Incorrect syntax! str <var> = <string>"