小编KBo*_*in9的帖子

我正试着从水龙头里得到一个字.以下函数sender来自UIGesture于UITextView句子.

- (IBAction)printWordSelected:(id)sender {
    NSLog(@"Clicked");

    CGPoint pos = [sender locationInView:self.view];
    UITextView *_tv = sentence;

    NSLog(@"Tap Gesture Coordinates: %.2f %.2f", pos.x, pos.y);

    //eliminate scroll offset
    pos.y += _tv.contentOffset.y;

    //get location in text from textposition at point
    UITextPosition *tapPos = [_tv closestPositionToPoint:pos];

    //fetch the word at this position (or nil, if not available)
    UITextRange * wr = [_tv.tokenizer rangeEnclosingPosition:tapPos withGranularity:UITextGranularityWord inDirection:UITextLayoutDirectionRight];

    NSLog(@"WORD: %@", [_tv textInRange:wr]);
}

这是我已经拥有的,但它将单词输出为NULL

我的主目录中有一个隐藏文件.profile，其内容如下：

MYSQL_HOME = /usr/local/mysql/bin/mysql
export PATH=$MYSQL_HOME/bin:$PATH

以下命令有效：

$ /usr/local/mysql/bin/mysql

但是mysql没有。如何更改路径以使命令起作用？我已经安装了MAMP，但不确定如何使用。谢谢！

AWS CLI命令aws emr list-clusters返回以下json.有没有办法通过bash或groovy我可以使用Name来获取Id？我不能只使用Id,因为我正在删除集群并使用相同的名称重建它们.所以我知道集群的名称是"my-cluster",我想以某种方式使用它来获取集群的Id.最后的情况是我实际上想要群集的公共DNS.

    {
        "Clusters": [
        {
            "Status": {
                "Timeline": {
                "ReadyDateTime": 1433200405.353,
                "CreationDateTime": 1433199926.596
            },
            "State": "WAITING",
            "StateChangeReason": {
                "Message": "Waiting after step completed"
                }
            },
            "NormalizedInstanceHours": 6,
            "Id": "j-3SD91U2E1L2QX",
            "Name": "my-cluster"
        },
        {
            "Status": {
                "Timeline": {
                    "ReadyDateTime": 1433200405.353,
                    "CreationDateTime": 1433199926.596
            },
            "State": "WAITING",
            "StateChangeReason": {
                "Message": "Waiting after step completed"
            }
        },
        "NormalizedInstanceHours": 6,
        "Id": "j-3S281UEK8L2LW",
        "Name": "my-cluster2"
        }
    ]
    }

<?php session_start();
$_SESSION['loggedIn'] = "no";
echo "Logged In: ". $_SESSION['loggedIn'];

if($_SESSION['loggedIn']=="yes"): 
    echo "logged in";
}
else{
    echo "not logged in";
}
?>

我只是想检查会话"loggedIn"是或否,但程序不打印任何内容.

为什么不打印任何东西？