我试图随着时间的推移将平方纹理纹理像素移动到纹理的中心.下面的代码正在做它的工作,除非我希望像素在到达几何体的中心(一个平面)时消失,而现在它只是变得越来越小,而时间增加,纹理看起来像收缩.

uniform float time;
varying vec2 vUv;
void main() {
vec2 center = vec2(0.5, 0.5);
vec2 newPosition = vec2(vUv.x + t * (center.x - vUv.x), vUv.y + t * (center.y - vUv.y);
gl_FragColor = texture2D( texture, vec2(newPosition.x, newPosition.y) );
}
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编辑:
把它想象成纹理中心的黑洞.

当我创建一个新的操作银行时,我需要自动将当前日期添加到我的数据库中。我正在使用休眠。谢谢
import java.io.Serializable;
import java.sql.Date;
import javax.persistence.*;
import org.hibernate.annotations.Generated;
import org.hibernate.annotations.GenerationTime;
@Entity
public class OperationBank implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
private String wordring;
private Double amount;
@Generated(GenerationTime.ALWAYS)
@Temporal(javax.persistence.TemporalType.DATE)
private Date dateoperation = new java.sql.Date(new java.util.Date().getTime());
@OneToOne
private Account account;
Run Code Online (Sandbox Code Playgroud) 我想知道如何使用javascript/jQuery获得不透明度参数.
例如:rgba(255,255,255,0.5)
我需要0.5
谢谢
需要一些帮助,请注意以下错误:
TypeError:'unicode'对象不支持项目分配
Ligne:menuDic [str(menu.id)] ['menuDishes'] [str(d.dish.dishType.name)] ['dishTypeName'] [str(d.dish.id)] = {}
def getDishOfTheWeek():
menuDic = Ddict(dict)
for menu in Menus.select().where(state = True):
menuDic[str(menu.id)]={}
menuDic[str(menu.id)]['menuId']=menu.id
menuDic[str(menu.id)]['menuName']=menu.name
menuDic[str(menu.id)]['menuCountry']=menu.country.name
menuDic[str(menu.id)]['menuDishes']={}
for d in DishMenuRels.select().where(menu = menu.id).join(Dishes).join(DishTypes).order_by('name')
menuDic[str(menu.id)]['menuDishes'][str(d.dish.dishType.name)] = {}
menuDic[str(menu.id)]['menuDishes'][str(d.dish.dishType.name)]['dishTypeName'] = d.dish.dishType.name
menuDic[str(menu.id)]['menuDishes'][str(d.dish.dishType.name)]['dishTypeName'][str(d.dish.id)] = {}
menuDic[str(menu.id)]['menuDishes'][str(d.dish.dishType.name)]['dishTypeName'][str(d.dish.id)]['dishId'] = d.dish.id
menuDic[str(menu.id)]['menuDishes'][str(d.dish.dishType.name)]['dishTypeName'][str(d.dish.id)]['dishState'] = d.dish.name
menuDic[str(menu.id)]['menuDishes'][str(d.dish.dishType.name)]['dishTypeName'][str(d.dish.id)]['dishType'] = d.dish.price
menuDic[str(menu.id)]['menuDishes'][str(d.dish.dishType.name)]['dishTypeName'][str(d.dish.id)]['dishName'] = d.dish.country.name
print json.dumps(menuDic, indent=5, sort_keys=True)
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谢谢
我想String用11ID 生成带有数字的数字.
例如:有一个帐户ID=12会给00000000012
之后我需要从字符串中检索此id.
例如:用绳子00000000022给出ID=22