我想在JS中动态更改背景,我的图像集是base64编码的.我尝试:
document.getElementById("bg_image").style.backgroundImage =
"url('http://amigo.com/300107-2853.jpg')";
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结果很完美,
但我没有做同样的事情:
document.getElementById("bg_image").style.backgroundImage =
"url('data:image/png;base64,iVBORw0KGgoAAAAAAAAyCAYAAAAUYybjAAAgAElE...')";
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也不
document.getElementById("bg_image").style.backgroundImage =
"data:image/png;base64,iVBORw0KGgoAAAAAAAAyCAYAAAAUYybjAAAgAElE...";
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有什么办法吗?
我使用Oxygen XMLTester for xPath选择器,支持XPath 2.0规范.所以我想知道是否有任何在线测试人员使用XPath 2.0规范. http://www.xmlme.com/XpathTool.aspx [http://www.xmlme.com/XpathTool.aspx][2] http://www.xpathtester.com/test [http://www.xpathtester的.com /测试] [3]
上述测试人员未能采用以下XPAth(2.0相当成功):/ list/sum(item/prices/price [@ currency ='USD'])和XML:
<list>
<item new='true'>
<title lang="en">Pop-Music DVD</title>
<author >K. A. Bred</author>
<year>2012</year>
<prices>
<price currency="USD">29.99</price>
<price currency="EUR">23.2</price>
</prices>
</item>
<item new='false'>
<title>Gone with the wind</title>
<author>M. Mitchell</author>
<year>1936</year>
<prices>
<price currency="USD">19.05</price>
<price currency="EUR">15</price>
</prices>
</item>
</list>
Run Code Online (Sandbox Code Playgroud) 如何找出我的网站正在刮?
我有点意见......
你会在这个列表中添加更多内容吗?
如果刮刀使用代理,可能适合/匹配哪些点?
因为我已经将yii应用程序移动到另一个共享主机,并且应用程序是runnig ... index.php?r =使用登录凭据的站点/登录我得到了warnig:
session_regenerate_id(): Cannot regenerate session id - headers already sent
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该actionLogin
"的代码:
public function actionLogin($name = null )
{
$model=new LoginForm;
if ($name) $model->username = $name;
if(isset($_POST['ajax']) && $_POST['ajax']==='login-form')
{
echo CActiveForm::validate($model);
Yii::app()->end();
}
if(isset($_POST['LoginForm']))
{
$model->attributes=$_POST['LoginForm'];
// validate user input and redirect to the previous page if valid
if (headers_sent($filename, $linenum))
{
echo "Headers have been sent in {$filename} line number is {$linenum}\n"
exit;
}
if($model->validate() && $model->login())
$this->redirect(Yii::app()->user->returnUrl);
}
// display the login form …
Run Code Online (Sandbox Code Playgroud) 有很多在线 json 查看器。然而,是否有任何可能使用 json 负载请求 POST以便传入的 json 字符串可能会被打印出来?不只是像往常一样复制/粘贴?
我已经安装了wampserver.但它始终是一个红色托盘图标.
local server - None of 2 services running
.80号港口没有被占用; 用Apache检查►服务►测试端口80:
警告:chmod():第68行的C:\ wamp\scripts\config.inc.php中的权限被拒绝无法修改文件C:\ WINDOWS\system32\drivers\etc\hosts要写入文件C:\ WINDOWS\system32\drivers\etc\hosts不可写*****使用端口80的测试*****=====在端口80上过滤命令netstat测试=====测试TCP端口80未找到与TCP协议关联的TCPv6测试未找到与TCP协议关联的端口80 =====尝试在端口80上打开套接字进行测试===== 您的端口80实际上未使用.
怎么了?
试图在以下位置更改Apache的端口号(均为81和8080)httpd.conf
:
听0.0.0.0:8080听[:: 0]:8080 ServerName localhost:8080
没有帮助.
我想为MS Word文本中的更正单词设置样式。由于无法在运行中更改文本样式,因此我想在现有段落中插入具有新样式的新运行...
for p in document.paragraphs:
for run in p.runs:
if 'text' in run.text:
new_run= Run()
new_run.text='some new text'
# insert this run into paragraph
# smth like:
p.insert(new_run)
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怎么做?
p.add_run()
在段落末尾添加一行,不是吗?
最好的办法是能够克隆运行(并在一定运行后插入)。这样,我们可以在新的/克隆的中复制原始运行的样式属性。
我可以管理该插入代码:
if 'text' in run.text:
new_run_element = CT_R() #._new()
run._element.addnext(new_run_element)
new_run = Run(new_run_element, run._parent)
...
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但是之后:
我来到了运行<=>
运算符的sql查询.<=>运算符是什么意思?
SELECT STR_ID, TEX_TEXT AS STR_DES_TEXT, IF( EXISTS( SELECT * FROM SEARCH_TREE AS SEARCH_TREE2 WHERE SEARCH_TREE2.STR_ID_PARENT <=> SEARCH_TREE.STR_ID LIMIT 1 ), 1, 0) AS DESCENDANTS FROM SEARCH_TREE
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这个sql是MySQL类型的.
我逐段迭代文档,然后我将每个段落文本拆分为句子.
(带空格的点)。与在整个段落文本中搜索相比,我将句子中的段落文本拆分为更有效的文本搜索。
然后代码在句子的每个单词中搜索错误,错误来自纠错数据库。我在下面展示了一个简化的代码:
from docx.enum.text import WD_BREAK
for paragraph in document.paragraphs:
sentences = paragraph.text.split('. ')
for sentence in sentences:
words=sentence.split(' ')
for word in words:
for error in error_dictionary:
if error in word:
# (A) make simple replacement
word = word.replace(error, correction, 1)
# (B) alternative replacement based on runs
for run in paragraph.runs:
if error in run.text:
run.text = run.text.replace(error, correction, 1)
# here we may fetch page break attribute and knowing current number …
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