小编Wil*_*Wil的帖子

希望你在这些时候一切都好。

我遇到了一个问题，希望你有更多的知识。

使用 'jq' 我想更改所有日期，例如。19731013（字符串）到 1973-10-13

[
    {
        "Mail": "john@example.com",
        "Name": "Smith",
        "Employee_Number": "000555",
        "First_Name": "John",
        "Company": "ACME",
        "Department": null,
        "Employment_Status": "Retiree",
        "Start_Date": "19770516",
        "Function_Start_Date": "19770516",
        "Group_Phone": "",
        "Job_Title": "Operations Manager Warehousing",
        "Sub_Group": "Exempts",
        "Location": "Tibuktu",
        "Organizational_Unit": null,
        "Date_of_Birth": "19560719",
        "Gender": "1"
    },
    {
        "Mail": "mary@example.com",
        "Name": "Smith",
        "Employee_Number": "000777",
        "First_Name": "Mary",
        "Company": "ACME",
        "Department": null,
        "Employment_Status": "Retiree",
        "Start_Date": "19770516",
        "Function_Start_Date": "19770516",
        "Group_Phone": "",
        "Job_Title": "Manager",
        "Sub_Group": "Exempts",
        "Location": "Tibuktu",
        "Organizational_Unit": null,
        "Date_of_Birth": "19560719",
        "Gender": "2"
    }
] 

是否可以substr(.Start_Date,1,5)"-"substr(.Start_Date,6,2)"-"substr(.Start_Date,8,3) …

我很惊讶.我忘了包括strtotime但是意识到它在任何情况下都有效.为什么这样做？

    if($_POST['active_to'] == ''  || $_POST['active_to'] >= '2038-01-19'){
        $postproduct->active_to = '2025-07-31';
    }else{
        $postproduct->active_to = $_POST['active_to'];
    }