小编Ton*_*ony的帖子

我正在尝试添加在autocompletetextview上选择项目时会做出反应的侦听器...任何人都可以帮助// phonename是autocompletetextview

PhoneName.setOnItemSelectedListener(new OnItemSelectedListener() {

            public void onItemSelected(AdapterView<?> arg0, View arg1,
                    int arg2, long arg3) {
                Toast.makeText(check.this," selected", Toast.LENGTH_LONG).show();

            }

            public void onNothingSelected(AdapterView<?> arg0) {
                // TODO Auto-generated method stub

            }
        });

<button type="button" id="okButton" onclick="funk()" value="okButton">Order now </button>
<script type="text/javascript">
    function funk(){
        alert("asdasd");
        <?php echo "asdasda";?>
    }
</script>

当按下按钮时我想执行php代码(此时回显asadasda)

我有一个数据表,并希望它将其导出到excel文件,它是一个wpf应用程序,我找到的所有解决方案都是针对Web应用程序asp.net请帮助...

我想设置监听器来监听无线状态,任何人都可以帮助我使用我的代码

import android.telephony.PhoneStateListener;
import android.telephony.TelephonyManager;

...

 TelephonyManager wTelephonyManager;

...

     wTelephonyManager=(TelephonyManager)getSystemService(Context.WIFI_SERVICE);
    wTelephonyManager.listen(new PhoneL(),PhoneStateListener.LISTEN_DATA_CONNECTION_STATE);
    connManager = (ConnectivityManager) getSystemService(CONNECTIVITY_SERVICE);

//这是我使用的事件,我想收听wifi更改,上面的代码全部在onCreate {}

class PhoneL extends PhoneStateListener

{   






    public void onWifiStateChanged(int state, String nesto)
    {
         mWifi = connManager.getNetworkInfo(ConnectivityManager.TYPE_WIFI);
            //mWifi.isConnectedOrConnecting()
             if(mWifi.isConnectedOrConnecting())
             {
                 Toast.makeText(WifiActivity.this,"Ima WIFI",Toast.LENGTH_LONG).show();     
             }
             else
             {
                 Toast.makeText(WifiActivity.this,"! NEMA WIFI",Toast.LENGTH_LONG).show(); 
             }


    }

}

//任何人都可以帮我创建一个监听器,它将监听wifi状态并检查wifi是否已连接或连接,如果不是我想通过3g/4g启用数据包流量

SELECT       *
FROM            [Table]
WHERE        (Izdava NOT LIKE NULL)

//如何检查Izdava是否为NULL

String tmp = txtPhoneName.getText().toString();
ContentResolver cr = getContentResolver(); 
Cursor cursor = cr.query(ContactsContract.Contacts.CONTENT_URI, null,  "DISPLAY_NAME = '" + tmp + "'", null, null);

if (cursor.moveToFirst()) {     
    String contactId = Cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts._ID));
    Cursor phones = cr.query(Phone.CONTENT_URI, null, Phone.CONTACT_ID + " = " + contactId, null, null); 

    while (phones.moveToNext()) {   
        String number = phones.getString(phones.getColumnIndex(Phone.NUMBER));
        number1 = number;
        int type = phones.getInt(phones.getColumnIndex(Phone.TYPE));  

        switch (type) {    
            case Phone.TYPE_HOME: 
            // do something with the Home number here...  
                break;          
            case Phone.TYPE_MOBILE:    
                // do something with the Mobile number …

可能重复:
如何将JavaScript变量传递给PHP？

如何获取不在<form>标记内的变量

var vvv = document.getElementById('vvv'); 

进入PHP

$variable=vvv.value;