小编Mar*_*lho的帖子

我有以下XML(string1):

<?xml version="1.0"?>
<root>
   <map>
      <operationallayers>
         <layer label="Security" type="feature" visible="false" useproxy="true" usePopUp="all" url="http://stackoverflow.com"/>
      </operationallayers>
   </map>
</root>

我有这段XML(string2):

<operationallayers>
    <layer label="Teste1" type="feature" visible="false" useproxy="true" usePopUp="all" url="http://stackoverflow.com"/>
    <layer label="Teste2" type="dynamic" visible="false" useproxy="true" usePopUp="all" url="http://google.com"/>
</operationallayers>

我使用函数simplexml_load_string将两者都导入到各自的var:

$xml1 = simplexml_load_string($string1);
$xml2 = simplexml_load_string($string2);

现在,我想为string2的节点'operationslayers'替换string1的节点'operationallayers',但是如何？

SimpleXMLElement类没有像DOM那样的方法'replaceChild'.