小编gym*_*y42的帖子

我正在尝试传递lambda。

def summation(n, term):
    if (n == 0):
        return
    else:
        return summation(n - 1, term) + term

print(summation(5, lambda x: x + 1))            

据我了解，lambda x : x + 1将成为term和term将评估到n + 1的功能，但是这是行不通的。谁能向我解释？

I was wondering how something like this would work.

int[] a = {5, 3, 4};

int[] b = {3, 4, 5};

a = b;

Does this mean that a will now reference b. So if I do a[0] it will be 3?

Also if this is the case what happens to the items in the old array?

为什么这样做：

def make_fib():
    cur, next = 0, 1
    def fib():
        nonlocal cur, next
        result = cur
        cur, next = next, cur + next
        return result
    return fib

工作方式不同于：

def make_fib():
    cur, next = 0, 1
    def fib():
        nonlocal cur, next
        result = cur
        cur = next
        next = cur + next
        return result
    return fib

我看到第二个怎么弄乱了，因为在cur = next和next = cur + next时，因为本质上它将变成next = next + next，但是第一个为什么运行不同？