小编mar*_*kus的帖子

嗨我试图在div中创建以下结构,但我只是需要一些帮助获得与CSS的startet.

宽度需要100%

我用的时候

 function __construct()
    {
      // open db
      $this->db = new mysqli(DB_HOST, DB_USER, DB_PASSWORD, DB_DATABASE);
      if (!$this->db)
        die(mysql_error());

      $this->db->query("SET NAMES 'utf8';");
    }


$result=$this->db->query("SELECT OrgNo, CompanyName FROM ematch WHERE CompanyName LIKE '%$word%';");
           $num=$result->num_rows;
          print $num; 
           $i=0;
            while ($i < $num) 
            {
                 $OrgNo=mysql_result($result,$i,"OrgNo");
                 $CompanyName=mysql_result($result,$i,"CompanyName");
                 $i++;
                 print $OrgNo.' '.$CompanyName.'<br>';
            }

我收到此错误:警告:mysql_result():提供的参数不是有效的MySQL结果资源,没有任何结果.

在UIButton上我设置了这样的标题

[myButton setTitle:@"Play"forState:UIControlStateNormal];

在另一个按钮上我设置了相同的标题

[myButton1 setTitle:@"Play"forState:UIControlStateNormal];

通过设置按钮标签我可以轻松比较.但是如何通过标题名称来比较按钮呢？

$gt = 'andrew';

mysql_connect('localhost', '', '');
mysql_select_db('database');
$result = mysql_query("SELECT gamertag FROM register WHERE gamertag = '".$gt."'");

while ($row = mysql_fetch_assoc($result)) {
    $gt = $row['gamertag'];
}

if($gt = 'andrew') {
    echo 'This gamertag has previously been registered!';
}