小编Jim*_*jbk的帖子

如何限制 Laravel 上特定用户的路由

我已向我的 auth 用户添加了一个角色列,它扩展了角色表

角色迁移

<?php

use Illuminate\Database\Migrations\Migration;
use Illuminate\Database\Schema\Blueprint;
use Illuminate\Support\Facades\Schema;

class CreateRolesTable extends Migration
{
    /**
     * Run the migrations.
     *
     * @return void
     */
    public function up()
    {
        Schema::create('roles', function (Blueprint $table) {
            $table->bigIncrements('id');
            $table->string('description');
            $table->timestamps();
        });
    }

    /**
     * Reverse the migrations.
     *
     * @return void
     */
    public function down()
    {
        Schema::dropIfExists('roles');
    }
}
Run Code Online (Sandbox Code Playgroud)

用户迁移

<?php

use Illuminate\Database\Migrations\Migration;
use Illuminate\Database\Schema\Blueprint;
use Illuminate\Support\Facades\Schema;

class CreateUsersTable extends Migration
{
    /**
     * Run the migrations.
     *
     * @return void
     */ …
Run Code Online (Sandbox Code Playgroud)

laravel

4
推荐指数
1
解决办法
2402
查看次数

在laravel中搜索后如何获得“未找到”结果

如果查询在数据库中没有匹配项,我希望得到“未找到”结果。

这是我的result.blade.php

@extends('layouts.app')

@section('content')
    @foreach ($result as $object)
        <div class="container pb-5">
            <div class="row justify-content-center">
                <div class="col-md-8">
                    <div class="card">
                        <div class="card-header">
                            <h3>Details for the animal</h3>
                        </div>
                        <div class="card-body">
                            <div class="col-12">
                                <p><strong>Serial Number: </strong>{{ $object->reference }}</p>
                                <p><strong>Animal Type: </strong>{{ $object->animal->type->category }}</p>
                                <p><strong>Farm: </strong>{{ $object->animal->user->name }}</p>
                                <p><strong>Date Of Birth: </strong>{{ $object->animal->dateOfBirth }}</p>
                                <p><strong>Farm Location: </strong>{{ $object->animal->user->address->city }}</p>
                                <p><strong>Clinic: </strong>{{ $object->animal->clinic->user->name ?? 'Was Not Checked by a Clinic' }}</p>
                                <p><strong>Clinic Location: </strong>{{ $object->animal->clinic->user->address->city }}</p>
                                <p><strong>Vaccination: </strong>
                                    {{ $object->animal->clinic->vaccine1 ?? 'N/A' }},
                                    {{ …
Run Code Online (Sandbox Code Playgroud)

laravel laravel-blade

0
推荐指数
1
解决办法
54
查看次数

标签 统计

laravel ×2

laravel-blade ×1