我正在创建具有多对多关系的两种类型的玩家和团队的模型和迁移.我正在使用sequelize model:create,但是看不到如何指定外键或连接表.
sequelize model:create --name Player --attributes "name:string"
sequelize model:create --name Team --attributes "name:string"
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创建模型后,我添加关联.在播放器中:
Player.belongsToMany(models.Team, { through: 'PlayerTeam', foreignKey: 'playerId', otherKey: 'teamId' });
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在团队中:
Team.belongsToMany(models.Player, { through: 'PlayerTeam', foreignKey: 'teamId', otherKey: 'playerId' });
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然后运行迁移
sequelize db:migrate
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有Player和Team的表,但数据库中没有连接表(也没有外键).如何创建外键和连接表?有没有关于如何做到这一点的权威指南?
我在IB中有以下内容,两个视图都打开了"使用自动布局"和"调整子视图大小".
我只是尝试将一个Autolayout View实例添加到容器视图中,使其边缘与容器视图的边缘相交.容器视图使用"自动布局"并且高度相同但宽度是两倍.这是代码:
- (IBAction)addSubviewButton:(id)sender
{
UIView *autolayoutView = [[[NSBundle mainBundle] loadNibNamed:@"AutolayoutView" owner:nil options:nil] objectAtIndex:0];
[self.containerView addSubview:autolayoutView];
[self.containerView addConstraint:
[NSLayoutConstraint constraintWithItem:autolayoutView
attribute:NSLayoutAttributeLeading
relatedBy:NSLayoutRelationEqual
toItem:self.containerView
attribute:NSLayoutAttributeLeading
multiplier:1
constant:0]];
[self.containerView addConstraint:
[NSLayoutConstraint constraintWithItem:autolayoutView
attribute:NSLayoutAttributeTrailing
relatedBy:NSLayoutRelationEqual
toItem:self.containerView
attribute:NSLayoutAttributeTrailing
multiplier:1
constant:0]];
[self.containerView addConstraint:
[NSLayoutConstraint constraintWithItem:autolayoutView
attribute:NSLayoutAttributeTop
relatedBy:NSLayoutRelationEqual
toItem:self.containerView
attribute:NSLayoutAttributeTop
multiplier:1.0
constant:0.0]];
[self.containerView addConstraint:
[NSLayoutConstraint constraintWithItem:autolayoutView
attribute:NSLayoutAttributeBottom
relatedBy:NSLayoutRelationEqual
toItem:self.containerView
attribute:NSLayoutAttributeBottom
multiplier:1.0 constant:0.0]];
}
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发生错误:
Probably at least one of the constraints in the following list is one you don't want...
(
"<NSIBPrototypingLayoutConstraint:0x8c364d0 'IB auto generated …
Run Code Online (Sandbox Code Playgroud) 我试图在Android Studio项目中为lib模块'lib1'执行gradle任务.它应该使用命令'gradlew assembleDebug'或'gradlew assemble'运行,但它永远不会运行.
task copy(type: Copy, dependsOn: ':lib1:assembleDebug') << {
println "copying"
}
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我尝试了一个没有依赖的简单任务,它似乎也从未运行过.
task hello << {
println 'hello world'
}
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这会运行,但它只在配置阶段.
task hello {
println 'hello world'
}
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在库模块组装之后,我需要在执行阶段获得一个副本.有什么线索怎么办?
我在一个实体上有一个布尔attr,生成的代码是:
@property (nonatomic, retain) NSNumber * countdownMode;
@dynamic countdownMode;
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实体保存为:
score.countdownMode = @(YES);
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fetchRequest具有以下谓词:
fetchRequest.predicate = [NSPredicate predicateWithFormat:@"countdownMode == YES"];
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由于某种原因,获取永远不会返回任何东西..任何想法?删除谓词后,将获取行.在调试器中我可以看到countdownMode是1.我也试过这些没有成功:
fetchRequest.predicate = [NSPredicate predicateWithFormat:@"countdownMode == %@", @YES];
fetchRequest.predicate = [NSPredicate predicateWithFormat:@"countdownMode == %d", YES];
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这似乎应该很简单,但它不会返回任何结果.感谢帮助.
我收到打字稿编译器错误。
[tsl] ERROR in /.../node_modules/@remirror/react-components/node_modules/@mui/base/useMenu/useMenu.d.ts(3,15)
TS1005: ',' expected.
ts-loader-default_e3b0c44298fc1c14
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在该文件中,导入导致了错误:
import { type MenuUnstyledContextType } from '../MenuUnstyled';
'type' is declared but its value is never read.ts(6133)
Module '"../MenuUnstyled"' has no exported member 'type'. Did you mean to use 'import type from "../MenuUnstyled"' instead?ts(2614)
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不过,这在 Typescript 3.8 中似乎是有效的,并且该应用程序使用typescript ^4.3.5
和@babel/preset-typescript ^7.14.5
。
// Explicitly pull out a value (getResponse) and a type (APIResponseType)
import { getResponse, type APIResponseType} from "./api";
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有什么想法如何解决吗?
objective-c ×2
android ×1
autolayout ×1
babeljs ×1
build.gradle ×1
core-data ×1
foreign-keys ×1
gradle ×1
javascript ×1
join ×1
node.js ×1
nspredicate ×1
sequelize.js ×1
typescript ×1