我正在尝试编写一个 python 装饰器来覆盖函数参数,但我真的不知道要在 inner() 函数中放置什么。在这里修改 args 的正确方法是什么?
def override(*override_args, **override_kwargs):
def outer(f):
def inner(*args, **kwargs):
...
...
return inner
return outer
@override('Cat')
def my_function(animal, **kwargs):
print animal
print kwargs
my_function('Mouse', k1='1', k2='10')
Run Code Online (Sandbox Code Playgroud) 我需要将 Auth0 用于我的 Flask-RESTful 应用程序。Auth0 有一个在视图函数上使用装饰器的示例requires_auth。
@app.route('/secured/ping')
@cross_origin(headers=['Content-Type', 'Authorization'])
@requires_auth
def securedPing():
return "All good. You only get this message if you're authenticated"
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对于 Flask-RESTful,我add_resource与Resource类app.route一起使用,而不是与视图函数一起使用。我该如何申请requires_auth到Version?
app = Flask(__name__)
API = Api(app)
CORS = CORS(app, resources={r'/api/*': {'origins': '*'}})
API.add_resource(Version, '/api/v1')
Run Code Online (Sandbox Code Playgroud) 我有以下脚本,它的意思是一个独立的Django脚本,所以我可以从命令行运行python my_script.py.它曾经与Django 1.8一起使用,在我升级到Django 1.11之后,我收到以下错误:
Traceback (most recent call last):
File "app.py", line 8, in <module>
django.setup()
File "C:\python27\lib\site-packages\django-1.11.5-py2.7.egg\django\__init__.py", line 22, in setup
configure_logging(settings.LOGGING_CONFIG, settings.LOGGING)
File "C:\python27\lib\site-packages\django-1.11.5-py2.7.egg\django\conf\__init__.py", line 56, in __getattr__
self._setup(name)
File "C:\python27\lib\site-packages\django-1.11.5-py2.7.egg\django\conf\__init__.py", line 41, in _setup
self._wrapped = Settings(settings_module)
File "C:\python27\lib\site-packages\django-1.11.5-py2.7.egg\django\conf\__init__.py", line 110, in __init__
mod = importlib.import_module(self.SETTINGS_MODULE)
File "C:\python27\lib\importlib\__init__.py", line 37, in import_module
__import__(name)
ImportError: Import by filename is not supported.
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这是我的python脚本
# standalone django setup
import os, sys, logging, django
prj_dir = os.path.abspath(os.path.dirname(os.path.dirname(__file__)))
logging.basicConfig(level=logging.INFO)
logging.info("PRJ_DIR: …Run Code Online (Sandbox Code Playgroud) 有人能告诉我为什么以下不匹配:
>>> re.search(r'(\d{2, 10})', '153')
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这个匹配:
>>> re.search(r'\d{3}', '153')
<_sre.SRE_Match object at 0x02110368>
Run Code Online (Sandbox Code Playgroud) 在Express中间件中,应该采用3个参数:request,response,next.但是,在我从书中复制的代码中的第二个中间件,但只使用请求,响应.这是什么原因?接下来是可选的?
var express = require("express");
var http = require("http");
var app = express();
app.use(function(request, response, next) {
console.log("In comes a " + request.method + " to " + request.url);
next();
});
app.use(function(request, response) {
response.writeHead(200, { "Content-Type": "text/plain" });
response.end("Hello, world!");
});
http.createServer(app).listen(3000);
Run Code Online (Sandbox Code Playgroud) 我收到以下错误,我该如何解决?
KeyError:'a'过程以退出代码1结束
s = """
a b c {a}
""".format({'a':'123'})
print s
Run Code Online (Sandbox Code Playgroud) 我正在尝试使用Python 3编写一个带有非ascii字符的CSV.
import csv
with open('sample.csv', 'w', newline='', encoding='utf-8') as csvfile:
spamwriter = csv.writer(csvfile, delimiter=' ',
quotechar='|', quoting=csv.QUOTE_MINIMAL)
spamwriter.writerow("?")
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当我打开Excel文件时,请参阅å—¨.我在这里做错了吗?
来自https://flutter.dev/docs/cookbook/maintenance/error-reporting,
runZoned<Future<void>>(() async {
runApp(CrashyApp());
}, onError: (error, stackTrace) {
// Whenever an error occurs, call the `_reportError` function. This sends
// Dart errors to the dev console or Sentry depending on the environment.
_reportError(error, stackTrace);
});
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但我的 IDE 说onError已弃用。
解决这个问题的正确方法是什么?我无法提供有关 runZonedGuarded 的任何示例。
我有一个 flash/flask_result 应用程序设置如下。如何向整个应用程序添加自定义全局 404 错误消息?我应该用龙卷风还是烧瓶来做?
from flask import Flask
from flask_cors import CORS
from flask_restful import Api
from flask_env import MetaFlaskEnv
from tornado.httpserver import HTTPServer
from tornado.ioloop import IOLoop
from tornado.wsgi import WSGIContainer
...
#setup api app
app = Flask(__name__)
app.config.from_object(Configuration)
API = Api(app)
# allow cross site request
CORS = CORS(app, resources={r"/api/*": {"origins": "*"}})
# system endpoints
API.add_resource(Version, '/api/version')
...
if __name__ == '__main__':
# start server
HTTP_SERVER = HTTPServer(WSGIContainer(app))
HTTP_SERVER.listen(port=app.config["PORT"])
IOLoop.instance().start()
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